NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

Using the quadratic formula, the solution for our problem is

The rocket splashes after 26.845 seconds.
The maximum of this function happens at the root of the derivative. Differentiating our function, we have

The root is

Then, the maximum height is

1029.99 meters above sea level.
Answer:
B = 61.75°
Step-by-step explanation:
The formula for the Law of Sines is given as:
a/ sin A = b/ sin B
In the question, we are given the following values
A = 56°, a = 16, b = 17
We are to solve for B
Hence,
16/ sin 56° = 17/sin B
Cross Multiply
sin B × 16 = sin 56° × 17
sin B = sin 56° × 17/16
sin B = 0.88
B = arc sin(0.88)
B = 61.74536°
Approximately B = 61.75°
Answer:
heyyyyyyyyy
Step-by-step explanation:
Free pionts thx
Answer:
x = 25
Step-by-step explanation:
Given
x - 5 = 20 ( isolate x by adding 5 to both sides )
x = 25
Your answer I’ll be choice C