Answer:
prokaryotes and eukaryotes I believe
POH = - log[OH^-]
pOH = - log[10^-6]
pOH = - (-6)
pOH = 6
knowing the ionization equation between pH and pOH in a solution at T = 25 degrees Celsius.
pH + pOH = 14
pH = 14 - pOH
pH = 14 - (6)
pH = 8.
I believe the pH of a substance with 10^-6 M of OH, would be 8.
Answer:
I have no idea
Explanation:
Good luck
okay so I'm typing random stuff because it says the answer to this question has to be 20 or more words and I just need my points
Grafting them! (ultimately, cloning)
