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maxonik [38]
4 years ago
15

A hydrochloric (HCI) solution has a molar concentration of 0.0045 M, calculate the [H3O+], [OH-] and pH of the solution. Remembe

r that Kw=
1.0x10-14M2
Chemistry
1 answer:
ExtremeBDS [4]4 years ago
8 0

Answer:

1) H30+ or H+ concentration is 0.0045M.

2) OH- concentration is 2.2 * 10^-12 M

3) pH =  2.35

Explanation:

1) HCl is strong acid so it completely dissociates which means you have

HCl------> H+ + Cl-

0-------> 0.0045 M, 0.0045M

We know now that H30+ or H+ concentration is 0.0045M.

2) H3O+ and OH- are related via the auto ionization of water.

Kw = 1.0*10^-14

(H3O) * (OH-) = 1.0*10^-14

OH- = ( 1.0*10^-14) / (0.0045) = 2.2 * 10^-12 M

3) pH measures the acidity based on the amount of hydrogen/hydronium ions in solution. H+ and H3O+ are both the same thing (either way it permissible to write)

The formula is pH= - log (H+) [now we just plug in the H+ we found)

pH = - log [0.0045] = 2.35

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A 265-mL flask contains pure helium at a pressure of 751 torrs. A second flask with a volume of 465 mL contains pure argon at a
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Answer:

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

Explanation:

Step 1: Data given

Volume of the flask helium = 265 mL

Pressure in the helium flask = 751 torr = 751/760 atm

Volume of the flask argon = 465 mL

Pressure in the argon flask = 727 torr = 727/760 atm

The total pressure exerted by a gaseous mixture is equal to the sum of the partial pressures of each individual component in a gas mixture.

Step 2: Calculate total volume

Total volume = 265 mL + 465 mL = 730 mL =  0.730 L

Step 3: Boyle's Law:

P1V1=P2V2

⇒ with P1 = total pressure gas exerts in its own flask

 ⇒ with V1 = volume of flask with stopcock valve closed

 ⇒ with P2 = partial pressure of gas exerts on total volume of both flasks when stopcock valve is opened  

 ⇒ with V2 = total volume of both flasks with stopcock valve opened

Helium using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of helium = 751 /760 = 0.98816 atm

 ⇒ with V1 = volume of helium = 0.265 L

 ⇒ with P2 = The new partial pressure of helium

 ⇒ with V2 = total volume = 0.730 L

(0.98816 atm)(0.265L)=P2(0.730L)

P2=0.359 atm

Argon using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of argon = 727/760 = 0.95658 atm

 ⇒ with V1 = volume of argon = 0.465 L

 ⇒ with P2 = The new partial pressure of argon

 ⇒ with V2 = total volume = 0.730 L

(0.95658 atm)(0.465L)=P2(0.730L)

P2=0.609 atm

Step 4: Convert pressure in atm to torr

Pressure helium = 0.359 atm = 272.8 torr

Pressure argon = 0.609 atm = 472.8 torr

Step 5: Calculate Total pressure

Ptotal = P(He)+P(Ar)

⇒ Pt  = total pressure of the gas mixture

⇒ P(He) = partial pressure of Helium

 ⇒ P(Ar)  = partial pressure of Argon

Pt = 272.8 torr + 472.8 torr

Pt = 745.6 torr

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

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Answer:

1. Fe(NO3)3 is C. Chemical formula

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3. Zn is C. Symbol

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