(-7a^4bc^3)(5ab^4c^2)

Suppose you know a certain parabola has a vertex of (2, 1) and a y-intercept of 4. By symmetry, you can conclude that the parabo

kodGreya [7K]

Answer:

A

Step-by-step explanation:

We are given a parabola with a vertex point of (2, 1) and a y-intercept of y = 4.

And we want to determine another point on the parabola.

Recall that a parabola is symmetric along the axis of symmetry, which is the x-coordinate of the vertex.

Note that since the y-intercept of the parabola is y = 4, this means that a point on our parabola is (0, 4).

To get from (2, 1) to (0, 4), we move two units left and three units up.

Since the parabola is symmetric along axis of symmetry, another point on the parabola will be two units right and three units up. This yields (2 + 2, 1 + 3) or (4, 4).

Our answer is A.

5 0

3 years ago

1. For the function f(x) = x2, Find the slope of the secant line joining (1,f(1)) and

goblinko [34]

The slope of the line connecting two points (a, b) and (c, d) is

(d - b) / (c - a)

i.e. the change in the y-coordinate divided by the change in the x-coordinate. For a function y = f(x), this slope is the slope of the secant line connecting the two points (a, f(a) ) and (c, f(c) ), and has a value of

(f(c) - f(a) ) / (c - a)

Here, we have

f(x) = x ²

so that

f (1) = 1² = 1

f (1.01) = 1.01² = 1.0201

Then the slope of the secant line is

(1.0201 - 1) / (1.01 - 1) = 0.0201 / 0.01 = 2.01

3 0

3 years ago

Please Help! Please write a sentence or more about the difference between each plot

topjm [15]

Box Plot has less variability in the data. We can determine this by the distances between the beginning of the data to the end (range) and the distances between lower quartile and the upper quartile (interquartile range).

Box #1
Range - 30
IQR - 15

Box #2
Range - approximately 23
IQR - approximately 9

Box #2 has less variation in the data because the distances between these 2 ranges are smaller meaning the data is closer together.

6 0

4 years ago

In March 2007, Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours. You wonder

Rasek [7]

Answer:

The hypotheses used in this situation

$H_0:\mu = 14.6$