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timurjin [86]
3 years ago
12

−2n < −12 how can i slove this?

Mathematics
2 answers:
Ket [755]3 years ago
8 0

Answer:

n>6

Step-by-step explanation:

you need to find the n variable by dividing

vampirchik [111]3 years ago
8 0

Answer:

n > 6

Step-by-step explanation:

You have to isolate n so you have to divide -2 by both sides.

  -2n < -12

  /-2      /-2

it's n > 6

You had to divide by a negative, which is why the symbol flipped around.

Hope this helps!!

-Ketifa

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Philip Morris wishes to determine if there is a difference between the proportion of women and proportion of men who smoke cigar
uranmaximum [27]

Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for the women and men who smoke respectively. The population proportion of women and men who smoke would be p1 and p2 respectively.

p1 - p2 = difference in the proportion of women and men who smoke.

The null hypothesis is

H0 : p1 = p2

p1 - p2 = 0

The alternative hypothesis is

Ha : p1 > p2

p1 - p2 > 0

it is a right tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For women

x1 = 14

n1 = 110

p1 = 14/110 = 0.13

For men,

x2 = 7

n2 = 95

p2 = 7/95 = 0.07

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (14 + 7)/(110 + 95) = 0.1

1 - pc = 1 - 0.1 = 0.9

z = (p1 - p2)/√pc(1 - pc)(1/n1 + 1/n2)

z = (0.13 - 0.07)/√(0.1)(0.9)(1/110 + 1/95)

z = 1.47

From the options given, the test statistic is

e. none of these is correct.

Since it is a right tailed test, we will look at the area to the right of z = 1.47. The p value would be

p value = 1 - 0.9292 = 0.078

Since alpha, 0.005 < than the p value, 0.078, then we would fail to reject the null hypothesis. Therefore, the data does not indicate that the proportion of women who smoke cigarettes is higher than the proportion of men who do at α=.005

8 0
3 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
3 years ago
Given: Rhombus ABCD. If mBAD is 64 degrees, then the mDCA is ___ degrees.
Marta_Voda [28]

Answer: 32 degrees

Step-by-step explanation:

6 0
2 years ago
Given any two arcs, the larger of the arcs is always called a minor arcTrueFalse
GrogVix [38]

When we have two arcs in a circle, one larger and one smaller, one will be called the minor arc and the other the minor arc.

The name of the arc depends on its size, for example, given the following green and yellow arcs, the green, which is smaller, will be the minor arc:

Therefore, the larger arc is always called Major arc, not minor arc.

The statement is False.

Answer: False

4 0
1 year ago
If line n bisects CE, find CD. ​
Artist 52 [7]

If it bisect, then using the Line Bisector Theorem, it must be equal.

So x+6=4x-21

get like terms on 1 side

x+6=4x-21

-x. +21

27= 3x

x=9

plug the x in

CD= 9+6

CD=15

8 0
3 years ago
Read 2 more answers
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