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2 years ago

Given: ∠1 and ∠2 are supplementary m∠1=112° Prove: m∠2=68°

Mathematics

2 answers:

slamgirl [31]2 years ago

6 0

supplementary angles are 180°

<1+<2=180°

given that <1=112°

112°+<2=180°

<2=180°-112°

<2=68°

katovenus [111]2 years ago

5 0

Answer:

supplementary angles are 180°

Step-by-step explanation:

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Irina18 [472]

Answer:

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Step-by-step explanation:

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2 years ago

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tia_tia [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Alex Ar [27]

Answer:

Step-by-step explanation:

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2 years ago

In △ABC, m∠A=52°, c=11, and m∠B=19°. Find a to the nearest tenth.

Ugo [173]

From the problem we have

In △ABC, m∠A=52°, c=11, and m∠B=19°.

Draw the diagram with the help of given information, (see the attached image)

Now using Sine Law in the Triangle ABC, we can write

Now from Triangle ABC , we can write

$\frac{a}{sin52}=\frac{11}{sin109} \\$

Now simplify , we get

$\Rightarrow a=\frac{11}{sin109}*sin52\\ \\ \Rightarrow a=\frac{11}{0.9455}*0.7880\\ \\ \Rightarrow a=9.1676 \approx 9.2\\$

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2 years ago

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Ann [662]

Answer:

Step-by-step explanation:

You are given only one space. Note that the term 6 shows up on both sides. Therefore, it is implying that you need to multiply the other two terms together. Do so:

9 x 5 = 45

45 is your answer.

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2 years ago