The man’s original salary was 100%. when increased by 10% , it becomes 110% which is $154 000.
so,
110% -> 154 000
1% -> $1400
100% -> $1400 x 100
= $140 000
<span> 8x/7+9=30 </span><span>
x = 147/8 = 18.375</span>
Answer:
df(t)/dt = 10 - 0.8f(t)
Step-by-step explanation:
The net rate of change, df(t)/dt = rate in - rate out
The rate in = rate litter forms on ground = 10 g/cm²/yr
Since f(t) is the amount of litter present at time, t, in g/cm² the rate out = rate of decomposition = the percentage rate × f(t) = 80% per year × f(t) = 0.8f(t) g/cm²/yr
Since df(t)/dt = rate in - rate out
df(t)/dt = 10 - 0.8f(t)
So the desired differential equation is
df(t)/dt = 10 - 0.8f(t)
Answer:
15-3
Step-by-step explanation:
15x3=45 or it could be 3-15