Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that
Putting , we get
Therefore, the measure of angle RQP is 33 degrees.
Given:
M is the midpoint of AB.
M(2,0) and A(-3, 3).
To find:
The coordinates of point B.
Solution:
Midpoint formula:
Let the coordinates of point B are (a,b). Then, using the midpoint formula, we get
On comparing both sides, we get
And,
Therefore, the coordinates of point B are (7,-3).
Answer: its A
Step-by-step explanation:
Answer:
Apothem: 6m
hypotenuse : slant height : 6√2 m
height :6m
volume: 288m2
Step-by-step explanation:
Hi, the correct values are: (image attached down below)
Base length= 12m
Slant height is actually = 6√2
So, to calculate the apothem (AC)we apply the Pythagorean theorem:
AB^2 = AC^2 + BC^2
√AB^2 -BC^2 = AC
AC = √(6√2)^2 - 6^2
AC =6 meters
Hypotenuse of ABC = AB =6√2 meters
Height = AC = 6 meters
Volume:
Volume of a pyramid = 1/3 x base area x height
area of a square = side length ^2 = 12^2
V= 1/3 x 12^2 x 6 =288 m2
