(16x3 + 40x2 + 72) (2x + 6)

1 answer:

Volgvan3 years ago

8 0

$(16x^3+40x^2+72)(2x+6)=32x^4+96x^3+80x^3+240x^2+144x+432=32x^4+176x^3+240x^2+144x+432$

In this case, you have to multiply each term of one parenthesis by each term in the second bracket. After receiving a number of factors need to be segregated and placed in the correct order.

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<img src="https://tex.z-dn.net/?f=%285%5E%7B3%7D%29%5E%7B-3%7D" id="TexFormula1" title="(5^{3})^{-3}" alt="(5^{3})^{-3}" align="

morpeh [17]

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$( { {5}^{3} })^{ - 3} \\ \\ which\:means \:that \: {5}^{3}\: is \:multiplied \:thrice\: with\: itself\\ \\ = {5}^{3 \times - 3} \\ \\ = {5}^{ - 9} \\ \\= \frac{1}{ {5}^{9} } \\ \\ = \frac{1}{5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5} \\ \\ = \frac{1}{1953125}$