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harina [27]
1 year ago
14

Solve 3 + 4x > -5 for x

Mathematics
1 answer:
Debora [2.8K]1 year ago
7 0

you have the following inequality:

3 + 4x > -5

in order to solve for x, proceed as follow:

3 + 4x > -5 subtract 3 both sides

4x > - 5 - 3

4x > -8 divide by 4 both sides

x > -8/4

x > -2

Hence, the solution to the given inequality is x > -2

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EPCIUCNO
cluponka [151]

Answer:

1 ⇒ D

2 ⇒ H

3 ⇒ B

4 ⇒ G

5 ⇒ A

6 ⇒ F

7 ⇒ E

8 ⇒ C

Step-by-step explanation:

* Lets explain how to solve the problem

- The left column has expressions and the right column has the

  equivalent expressions

- We must find the equivalent letter for each number

1.

# 7(12)

∵ 12 can be a sum of two numbers

∴ The equivalent expression to 7(12) is 7(8 + 4)

∴ 1 ⇒ D

2.

# 3(15)

∵ 3 can be a sum of two numbers

∴ The equivalent expression to 3(15) is (2 + 1)(15)

∴ 2 ⇒ H

3.

# 3a + 9

∵ 3 and 9 have a common factor 3

∵ 3a + 9 ⇒ divide them by 3

∵ 3a ÷ 3 = a and 9 ÷ 3 = 3

∴ 3a + 9 = 3(a + 3)

∴ The equivalent expression to 3a + 9 is 3(a + 3)

∴ 3 ⇒ B

4.

# 9a + 3

∵ 9 and 3 have a common factor 3

∵ 9a + 3 ⇒ divide them by 3

∵ 9a ÷ 3 = 3a and 3 ÷ 3 = 1

∴ 9a + 3 = 3(3a + 1)

∴ The equivalent expression to 9a + 3 is 3(3a + 1)

∴ 4 ⇒ G

5.

# 5 + 15a

∵ 5 and 15 have a common factor 5

∵ 5 + 15a ⇒ divide them by 5

∵ 5 ÷ 5 = 1 and 15a ÷ 5 = 3a

∴ 5 + 15a = 5(1 + 3a)

∴ The equivalent expression to 5 + 15a is 5(1 + 3a)

∴ 5 ⇒ A

6.

# 10 + 5a

∵ 10 and 5 have a common factor 5

∵ 10 + 5a ⇒ divide them by 5

∵ 10 ÷ 5 = 2 and 5a ÷ 5 = a

∴ 10 + 5a = 5(2 + aa)

∴ The equivalent expression to 10 + 5a is 5(2 + a)

∴ 6 ⇒ F

7.

# 3x + 6y + 9z

∵ The coefficient of x , y , z have a common factor 3

∵ 3x ÷ 3 = x

∵ 6y ÷ 3 = 2y

∵ 9z ÷ 3 = 3z

∴ 3x + 6y + 9z = 3(x + 2y + 3z)

∴ The equivalent expression to 3x + 6y + 9z is 3(x + 2y + 3z)

∴ 7 ⇒ E

8.

# 3x + 3y + 3z

∵ The coefficient of x , y , z have a common factor 3

∵ 3x ÷ 3 = x

∵ 3y ÷ 3 = y

∵ 3z ÷ 3 = z

∴ 3x + 3y + 3z = 3(x + y + z)

∴ The equivalent expression to 3x + 3y + 3z is 3(x + y + z)

∴ 8 ⇒ C

4 0
2 years ago
HELP FAST NOW PLEASE IM HAVING TROUBLE!!
tia_tia [17]
First triangle=bxh/2
                  =3x4/2
                 =6in squared
rectangle=l x w
              =3 x 10
               =30in squared

trapezoid=3+5x2/2
                 =8in squared
                6 + 30 + 8
                   =44 in squared

7 0
3 years ago
Read 2 more answers
Indicate the method you would use to prove the two 's . If no method applies, enter "none".
Andrei [34K]
Answer: ASA method must be applied to the given triangles to prove then congruent.


In two triangles, if two angles and their included side are congruent then the two triangles are said to be congruent .This method is known as Angle-Side -Angle postulate(ASA).
In the given triangles one side with their corresponding angles are equal. Therefore by ASA postulate they are congruent.
There we can see no other sides are given equal therefore all the other options cannot be applied.

you are lucky I had this test yesterday and I have the answer is ASA my math teacher said it was fine
6 0
3 years ago
You are traveling at 75 miles per hour on a straight stretch of highway in Nevada. It is noon now. When will you arrive at the n
Levart [38]
Right now it is noon..... you are traveling 75 miles per hour meaning you'll move 75 miles... every hour. so you're 120 miles away so now we need to figure out the time.... to do this we already know 1 hour is 75 miles so now you can subtract one hour 120-75= 45 so 75 per hour, what would 45 be?..... so we can set up a fraction to figure out how long it takes to travel one minute.... so 60/75(the 60 is for minutes in an hour). which is .8 of a second to travel one mile so.... now you can multiply to check your work. .8*75=60 mins.... so now multiply.8*45(miles left)=36 so you'd get there at 1:36 it would take an hour and 36 mins to get to your destination going 75mph
6 0
3 years ago
25 POINTS! MATCHING PROBLEM!
Nataly_w [17]
1. f(x) = 1
2. f(x) = x
3. f(x) = 5 - x
4. f(x) = 3
8 0
3 years ago
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