For this case we have the following vectors:
The dot product of two vectors is a scalar.
The point product consists of multiplying component by component and then adding the result of the multiplication of each component.
For the product point of the vectors a and b we have:
Answer:
The product point of the vectors a and b is:
You would need two different lines to complete this as lines cannot be both parallel and perpendicular (these are opposites). The answers would be:
Parallel: x = 2
Perpendicular: y = -2
In order to find these, we first need to see that the original line of x = -1 is a horizontal line. Therefore, any line that is parallel should be horizontal as well. To get a horizontal line through the point (2, -2), the only option is x = 2.
Similarly, with the perpendicular line, if the original line is horizontal, the new line must be vertical. The only vertical line that goes through (2, -2) is y = -2.
Given:
A figure of triangles.
To find:
Whether the triangles SPT and triangle QPR are similar.
Solution:
In triangle SPT and triangle QPR,
(Given)
(Common angle)
In triangles SPT and triangle QPR, two corresponding angles are congruent. So, by AA property of similarity both triangles are similar.
Therefore, yes, the triangle SPT and triangle QPR similar. Option A is correct.
Answer:
n = 2
Step-by-step explanation:
Given
(n - 4) - 3 = 3 - (2n + 3)
Multiply through by 2 to clear the fraction
n - 4 - 6 = 6 - 2(2n + 3) ← distribute
n - 10 = 6 - 4n - 6 ( add 4n to both sides )
5n - 10 = 0 ( add 10 to both sides )
5n = 10 ( divide both sides by 5 )
n = 2
