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Lady_Fox [76]
2 years ago
14

Need help please help please I will give brainless

Mathematics
2 answers:
FinnZ [79.3K]2 years ago
6 0

Answer:

Question number 2 is A

And so is question number 3

Step-by-step explanation:

It says for 15 minus a number (meaning a variable like x or y) divided by 2 equals eleven

so 15 - y/2 = 11

For question number 3 it says the insurance company wants 100 dollars in deduction fee and then it will pay 80 percent or 0.8 of the medical costs.  so we get

0.8(960- 100)

The reason why we subtract 100 is because we paid the insurance company 100 dollars, so that is our own money going to the medical bills.

then we multiply 0.8 by 860

inessss [21]2 years ago
3 0

Answer:

B

Step-by-step explanation:

You might be interested in
What are the zeros of this polynomial and state their multiplicity at each <br> y=(x-5)(x+2)^2
N76 [4]

Answer:

C.

Step-by-step explanation:

The zeros of a polynomial are the x-intercepts of the function. To find them, we factor the polynomial and set each factor equal to 0.

This polynomial is already factored so set each to 0 and solve for x.

x-5=0\\x=5\\(x+2)^{2}=0 \\(x+2)=0\\x=-2

This means x=-2, 5. Each zero or root has a multiplicity - the number of times the factor occurs. This is also known as the exponent of the factor expression.

(x+5) occurs once since it has exponent 1.

(x+2)^{2} occurs twoce since it has exponent 2.

x=5 mult. 1, x=-2 mult. 2



7 0
3 years ago
What is the answer to 39=3m-15
Vladimir [108]
39=3m-15
39+15=3m
54=3m
54/3=3m/3
m=18
4 0
2 years ago
Read 2 more answers
The average annual cost (including tuition, room, board, books and fees) to attend a public college takes nearly a third of the
Crazy boy [7]

Answer:

a) Private Colleges

Sample mean = 42.5 thousand dollars

Standard deviation = S1 = 6.62 thousand dollars.

Public colleges

Sample mean = 22.3 thousand dollars

Standard deviation = 4.34 thousand dollars

b) The difference in sample mean for both cases = 42.5 - 22.3 = 20.2 thousand dollars

The average amount of going to a Private college is 20.2 thousand dollars more than the average cost of going to public colleges

c) 95% confidence interval for a sampling distribution of the difference of the cost of private and public colleges is given as

(15.0, 25.4) thousand dollars.

Step-by-step explanation:

Private colleges.

52.8 43.2 45.0 33.3 44.0 30.6 45.8 37.8 50.5 42.0

Public colleges.

20.3 22.0 28.2 15.6 24.1 28.5 22.8 25.8 18.5 25.6 14.4 21.8

a) Calculate sample mean and standard deviation for both data set.

Mean = (Σx)/N

where N = Sample size

Σx = sum of all variables

Private colleges

Σx = (52.8+43.2+45.0+33.3+44.0+30.6+45.8+37.8+50.5+42.0) = 425

N = 10

Mean = 425/10 = 42.5 thousand dollars

Standard deviation = S1 = √[Σ(x - xbar)²/N]

Σ(x - xbar)² = (52.8-42.5)² + (43.2-42.5)²

+ (45.0-42.5)² + (33.3-42.5)²

+ (44.0-42.5)² + (30.6-42.5)² + (45.8-42.5)² + (37.8-42.5)² + (50.5-42.5)² + (42.0-42.5)² = 438.56

N = 10

Standard deviation = √[Σ(x - xbar)²/N]

Standard deviation = √(438.56/10) = 6.62 thousand dollars

Public colleges

Mean = (Σx)/N

Σx =

(20.3+22.0+28.2+15.6+24.1+28.5+22.8+25.8+18.5+25.6+14.4+21.8) = 267.6

N = 12

Mean = (267.6/12) = 22.3 thousand dollars

Standard deviation = √[Σ(x - xbar)²/N]

[Σ(x - xbar)²

(20.3-22.3)² + (22.0-22.3)² + (28.2-22.3)² + (15.6-22.3)² + (24.1-22.3)² + (28.5-22.3)² + (22.8-22.3)² + (25.8-22.3)² + (18.5- 22.3)² + (25.6-22.3)² +(14.4-22.3)+(21.8-22.3) = 225.96

N = 12

standard deviation = s2 = √(225.96/12) = 4.34 thousand dollars

b) The difference in sample mean for both cases = 42.5 - 22.3 = 20.2 thousand dollars

The average amount of going to a Private college is 20.2 thousand dollars more than the average cost of going to public colleges.

c. Develop a 95% confidence interval of the difference between the annual cost of attending private and pubic colleges.

95% confidence interval, private colleges have a population mean annual cost $ to $ more expensive than public colleges.

To combine the distribution in this manner,

Sample mean of difference = 20.2 thousand dollars

Combined standard deviation of the sampling distribution = √[(S1²/n1) + (S2²/n2)]

= √[(6.62²/10) + (4.34²/12)] = 2.44 thousand dollars

Confidence interval = (Sample mean) ± (Margin of error)

Sample mean = 20.2

Margin of error = (critical value) × (standard deviation of the sampling distribution)

standard deviation of the sampling distribution = 2.44

To obtain the critical value, we need the t-score at a significance level of 5%; α/2 = 0.025

we obtain the degree of freedom too

The degree of freedom, df, is calculated in the attached image.

df = 15

t (0.025, 15) = 2.13145 from the tables

Margin of error = 2.13145 × 2.44 = 5.20

Confidence interval = (Sample mean) ± (Margin of error)

= (20.2 ± 5.2) = (15.0, 25.4)

Hope this Helps!!!

8 0
3 years ago
55 POINTS!!!!!!
vladimir1956 [14]
A
c
d
b
c
a
hope it helped!
5 0
3 years ago
Find the solution of the system of equations shown on the graph
svet-max [94.6K]

Answer:

  (7, 9)

Step-by-step explanation:

The lines cross at point (7, 9). This is the solution.

__

If we assume the variables being graphed are x and y, then the solution is ...

  • x = 7
  • y = 9
7 0
3 years ago
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