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ser-zykov [4K]
2 years ago
6

WILL MARK BRAINLIEST in detail, what would you do in order to graph y = 3x -5

Mathematics
1 answer:
Hunter-Best [27]2 years ago
5 0

So first, you need to identify the parts of this equation.

3x is the slope of the line, which is \frac{3}{1}.

-5 is the y-intercept. or the part of the line that touches the y-axis.

The first thing you want to do is plot the y-intercept. SO, go to the y-axis and find -5. Plot your point there.

Now, use the slope \frac{3}{1} to find your next plot. Since slope is \frac{rise}{run}, you go up three, and over to the right one.

Now, draw a line connecting the dots. Your slope should be positive and look like > /

~theLocoCoco

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Answer:

D and B

Step-by-step explanation:

Hope this helped

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Which set of ordered pairs has point symmetry with respect to the origin (0, 0)?
Leya [2.2K]

Answer:

(-8, 3), (8, -3)

Step-by-step explanation:

Point symmetry about origin means reflection of the given point about the origin.

The reflection of a point about the origin will cause the 'x' and 'y' value of the point to change its sign.

Therefore, the coordinate rule for point symmetry about the origin is given as:

(x,y)\to (-x,-y)

Now, let us check each of the given options.

Option 1:

(-8, 3), (8, -3)

Now, if (x, y) = (-8, 3), then its point symmetry is given as (-(-8), -3) = (8, -3)

So, option 1  is correct.

Option 2:

(-8, 3), (-3, 8)

Now, if (x, y) = (-8, 3), then its point symmetry is given as (-(-8), -3) = (8, -3) ≠ (-3, 8)

So, option 2 is not correct.

Option 3:

(-8, 3), (-8, -3)

Now, if (x, y) = (-8, 3), then its point symmetry is given as (-(-8), -3) = (8, -3) ≠ (-8, -3)

So, option 3 is not correct.

Option 4:

(-8, 3), (8, 3)

Now, if (x, y) = (-8, 3), then its point symmetry is given as (-(-8), -3) = (8, -3) ≠ (8, 3)

So, option 4 is not correct.

Hence, only option 1 is correct.

5 0
3 years ago
5y^2+5−4−4y^2+5y^2−4x^3 −1
vredina [299]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{4 {x}^{3}  + 6 {y}^{2} }}}}}

Step-by-step explanation:

\sf{5 {y }^{2}  + 5 - 4 - 4 {y}^{2}  + 5 {y}^{2}  - 4 {x}^{3}  - 1}

Collect like terms

⇒\sf{ 4 {x}^{3}  + 5 {y}^{2}  - 4 {y}^{2}  + 5 {y}^{2}  + 5 - 4 - 1}

⇒\sf{4 {x}^{3}  +  {y}^{2}  + 5 {y}^{2}  + 5 - 4 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 5 - 4 - 1}

Calculate

⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 1 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2} }

Hope I helped!

Best regards! :D

6 0
3 years ago
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