Answer:
The solutions will contain an infinite amount of negative numbers.
 
        
             
        
        
        
I think it is $2.40 (but I am not too sure) try to get some more people to answer.
Good Luck!!!!!☺☻☺☻☺☻
        
                    
             
        
        
        
Answer:
0.2941 = 29.41% probability that it was manufactured during the first shift.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
 is the probability of both A and B happening.
 is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Defective
Event B: Manufactured during the first shift.
Probability of a defective item:
1% of 50%(first shift)
2% of 30%(second shift)
3% of 20%(third shift).
So

Probability of a defective item being produced on the first shift:
1% of 50%. So

What is the probability that it was manufactured during the first shift?

0.2941 = 29.41% probability that it was manufactured during the first shift.
 
        
             
        
        
        
There would be 1,320 different ways, just multiply all the possible front runners 12 second runners 11 and third runners 10, 12x11x10=1,320
        
             
        
        
        
I would say b... hope this helps!!!!!!!