Use integration by parts:
![u = x ............ dv = sec^2 x \\ \\ du = dx ....... v = tan x \\ \\ =x tan( x) - \int tan (x) dx](https://tex.z-dn.net/?f=u%20%3D%20x%20%20............%20%20%20%20%20%20%20%20dv%20%3D%20sec%5E2%20x%20%5C%5C%20%20%5C%5C%20du%20%3D%20dx%20%20.......%20v%20%3D%20tan%20x%20%5C%5C%20%20%5C%5C%20%3Dx%20tan%28%20x%29%20-%20%5Cint%20tan%20%28x%29%20dx)
For the integral of tangent, multiply by sec on top and bottom.
![= x tan(x) - \int \frac{sec (x) tan(x)}{sec(x)} dx](https://tex.z-dn.net/?f=%3D%20x%20tan%28x%29%20-%20%5Cint%20%5Cfrac%7Bsec%20%28x%29%20tan%28x%29%7D%7Bsec%28x%29%7D%20dx)
Use u-substitution:
![u = sec(x) \\ \\ du = sec(x) tan(x) dx \\ \\ =x tan(x) - \int \frac{du}{u} \\ \\ =x tan(x) - ln |u| + C \\ \\ = x tan(x) - ln|sec(x)| + C](https://tex.z-dn.net/?f=u%20%3D%20sec%28x%29%20%5C%5C%20%20%5C%5C%20du%20%3D%20sec%28x%29%20tan%28x%29%20dx%0A%20%5C%5C%20%20%5C%5C%20%3Dx%20tan%28x%29%20-%20%5Cint%20%5Cfrac%7Bdu%7D%7Bu%7D%20%20%5C%5C%20%20%5C%5C%20%3Dx%20tan%28x%29%20-%20ln%20%7Cu%7C%20%2B%20C%20%5C%5C%20%20%5C%5C%20%3D%20x%20tan%28x%29%20-%20ln%7Csec%28x%29%7C%20%2B%20C)
Answer can also be written as
3x+14 + 7x+4=118
(As, sum of opposite interior angles of a triangle= exterior angle)
∴ 10x +18= 118
10x= 118-18
10x= 100
x=10
∴ angle F=7x+4
=7*10+4
=70+4
=74
Answer:
47+2a+4b-5c
Step-by-step explanation:
hope this helps, have a great day/night
This is essentially a rule in the unit of radicals, where n✔️X^m = X^m/n. If the value of m is equal to n, as in 2✔️3^2 it would simply be 3^2/2 which is nothing but 3^1 = 3. Basically, the m value can be greater than n and or less than n, but if it is equal the m and n values cancel out.