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max2010maxim [7]
3 years ago
15

A piece of metal with a mass of 140. g is placed in a 50 mL graduated cylinder. The water level rises from 20. mL to 41 mL. What

is the density of the metal?
Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0
1. An object submerged in water, rises up a volume of water equal to the volume of the object. 


2.   1 milliliter of water has a volume of 1 cubic centimeters. 


3.    Mass= Density * Volume
-----------------------------------------------------------------------------------------------------


The water level rises from 20.mL to 41.mL means that a volume of 21mL of water has been displaced.              

This means that the volume of the object is 21 cm cubed.        (by 1 and 2)

By 3, the density of the piece of metal is:

Density=Mass/Volume=140 g / 21 cm^3= (140/21) g/cm^3=6.67 g/cm^3


Answer: 6.67 g/cm^3
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Round 398.223 to the nearest ten
Rufina [12.5K]

Answer:

400

Step-by-step explanation:

Method for rounding:

Look at the number 1 place before the place you are rounding to.

If it is greater than 4: round up

otherwise: round down.

Ok,

here the number we're looking at is 8 cuz' 8 is in the ones place.

8 is bigger than 4 so we round up.

398.223 becomes 400

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4 out of 12 family rides are for young riders under the age of 5. What fraction has the same value as 4/12?
Luda [366]

I think the answer is 1/3 because you can simplify 4/12 into 2/6 and that can also be simplify into 1/3. Sorry if I am wrong let me know if i'm right

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3 years ago
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Find the arc length of ABC .
Salsk061 [2.6K]

Answer:

C.

Step-by-step explanation:

Since the radius of the circle is 12 units, we can calculate the circumference.

2 * pi * r = 2 * pi * 12 = 24 * pi = 24pi.

The arc angle is 240 degrees, and the whole circle would be 360 degrees. So, we can set up an equation.

\frac{24\pi }{360} =\frac{x}{240}

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Hope this helps!

4 0
3 years ago
1).Calculate T, when sample mean is 120, population mean is 100, standard deviation is 20 and smaple size is 10 using levels of
Sonbull [250]

Answer:

t=\frac{120-100}{\frac{20}{\sqrt{10}}}=3.16  

p_v =2*P(t_{9}>3.16)=0.012  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and the true mean is significantly different from 100 at 5% of significance.  

Step-by-step explanation:

Data given and notation

\bar X=120 represent the sample mean  

s=20 represent the standard deviation for the sample

n=10 sample size  

\mu_o =100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is different from 100, the system of hypothesis would be:  

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{120-100}{\frac{20}{\sqrt{10}}}=3.16  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=10-1=9

Conclusion

Since is a tao tailed test the p value would be:  

p_v =2*P(t_{9}>3.16)=0.012  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and the true mean is significantly different from 100 at 5% of significance.  

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jonny [76]
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Or you could do it this way
Steps:
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4 0
4 years ago
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