Notice the grid, the points are (-5, -2) and (4, -1), thus
![\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~{{ 4}} &,&{{ -1}}~) % (c,d) &&(~{{ -5}} &,&{{ -2}}~) \end{array}~~ % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ d=\sqrt{[-5-4]^2+[-2-(-1)]^2}\implies d=\sqrt{(-5-4)^2+(-2+1)^2} \\\\\\ d=\sqrt{(-9)^2+(-1)^2}\implies d=\sqrt{81+1}\implies d=\sqrt{82}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%26%26x_2%26%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26%26%28~%7B%7B%204%7D%7D%20%26%2C%26%7B%7B%20-1%7D%7D~%29%20%0A%25%20%20%28c%2Cd%29%0A%26%26%28~%7B%7B%20-5%7D%7D%20%26%2C%26%7B%7B%20-2%7D%7D~%29%0A%5Cend%7Barray%7D~~%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%29%5E2%20%2B%20%28%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ad%3D%5Csqrt%7B%5B-5-4%5D%5E2%2B%5B-2-%28-1%29%5D%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B%28-5-4%29%5E2%2B%28-2%2B1%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ad%3D%5Csqrt%7B%28-9%29%5E2%2B%28-1%29%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B81%2B1%7D%5Cimplies%20d%3D%5Csqrt%7B82%7D)
Given:
A number line from -10 to 10 with 20 tick marks.
Point D is 1 tick mark to the left of 5.
To find:
The integer value that represents point D.
Solution:
A number line from -10 to 10 with 20 tick marks. It means, each mark represents the integer values from -10 to 10.
We know that, as we move towards left on a number line the value decreases and as we move towards right the value increases.
Point D is 1 tick mark to the left of 5. It means, point D represents the integer value which is 1 less than 5.
Therefore, point D represents the integer 4.
For short you call this scientific notation.
FIRST
Count how many time you need to move the decimal over to make your single digit more then 1 and less then 10. So we will erase the 0's as we go along.
167000,000,000,000
So in this case we want to make the single digit 1.67 so it can be greater then 1 and less then 10
So now we see how many times we need to move the decimal and when you cant see the decimal just imagine it at the very end of the problem
167000,000,000,000
(For the mods out there I copied and pasted the bold number so i didn't have to take a while to retype the whole number. Thanks.)
SO NOW I get 14 because that's how many spots the decimal moved over.
Now since we need to right it in SN we need to write out this
X*10^X
The exponent X stands for how many times we moved the decimal over. I got 14 so we have that exponent
X*10^14
NOW We need to fiqure out X.... X was just the number we made greater then one and less then 0.
So thats 1.67
So we get
1.67*10^14
Did this help? <3
