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Svetllana [295]
4 years ago
13

217 pens; 7 cases??????

Mathematics
2 answers:
MariettaO [177]4 years ago
5 0
Divide 7 and 217 and you have 31 so there are 31 pens in each case
s344n2d4d5 [400]4 years ago
5 0
If the 217 pens were to be equally distributed among 7 cases, each case can hold 31 pens.
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The center of a circle is (0, -8). The radius is 9. What is the equation of the circle? Select all that apply.
taurus [48]

Answer:

x² + (y + 8)² = 81

Step-by-step explanation:

Centre (h,k) = (0,-8)

radius (r) = 9

(x - h)² + (y - k)² = r²

(x - 0)² + (y + 8)² = 9²

x² + (y + 8)² = 81

8 0
3 years ago
A researcher surveyed 220 residents of a city about the number of hours they
olga55 [171]

Answer:

Margin of error of 0.0485 hours.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this question:

\sigma = 0.35, n = 220

The margin of error is of:

M = z\frac{\sigma}{\sqrt{n}}

M = 1.96\frac{0.35}{\sqrt{200}}

M = 0.0485

Margin of error of 0.0485 hours.

5 0
3 years ago
Kyle has 105 baseball cards and must give 2/5 of his cards away.
klasskru [66]
1. 42 cards
2. 3/5 of his cards
5 0
3 years ago
The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t
wolverine [178]

Answer:

a) The implied differential equation is \frac{dN}{725 - N} = kdt

b) The general equation is N = 725 - C e^{-kt}

c) The particular equation is N = 725 - 325 e^{-0.49t}

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, \frac{dN}{dt} \alpha (725 - N(t))

\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt

Integrating both sides of the equation

\int {\frac{1 }{725 - N}} \, dN  = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}

When t = 0, N = 400

400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325

When t = 3,  N = 650

650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49

The equation for the population becomes:

N = 725 - 325 e^{-0.49t}

At t = 5, the population becomes:

N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697

N(5) = 700 ( to the nearest 50)

6 0
3 years ago
WHOEVER ANSWERS CORRECTLY GETS BRAINLIEST
VashaNatasha [74]
I = Prt
P = i / rt
P = 288 / (0.016 * 3)
P = 288 / 0.048
P = 6,000

answer
He should deposit $6,000
5 0
3 years ago
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