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3 years ago

(25 POINTS) Write the inequality of the following graph?

Mathematics

1 answer:

Ainat [17]3 years ago

5 0

Answer:

f(x) > -x + 2

Step-by-step explanation:

First I found the equation of the line.

The y intercept is at 2 so I know to add 2 at the end

The slope is -1 since it is going downwards

Since the top side is shaded, that represents greater than, if it was shaded downwards, it would be less than

Putting all that together, the equation is f(x) > -x + 2

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EXPERTS/ACE/GENIUSES PLZ HELP

Marta_Voda [28]

Sqrt(15) would be irrational

Answer is B

5 0

3 years ago

Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178

kompoz [17]

Answer: [911,∞)

Step-by-step explanation:

Given: S be the number of cans collected by Shane.

Since, Abha collected 178 more cans than Shane did.

Then, the number of cans collected by Abha = S+178

Also, Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling.

So, $S+178+S\geq2000$

$\\\Rightarrow\ 2S\geq2000-178\\\Rightarrow2S\geq1822\\\Rightarrow\ S\geq911$

Hence, the solution set of the inequality will be [911,∞)

4 0

3 years ago

Solve the following question. *

n200080 [17]

Answer:

The mean of x and y is equal to t.

Step-by-step explanation:

Given that,

The mean of t and t+2 is x.

The mean of t and t-2 is y.

i.e.

$x=\dfrac{t+t+2}{2}\\\\x=(t+1)$

and

$y=\dfrac{t+t-2}{2}\\\\x=(t-1)$

The mean of x and y is :

$M=\dfrac{x+y}{2}\\\\M=\dfrac{(t+1)+(t-1)}{2}\\\\M=\dfrac{2t}{2}\\\\M=t$

Hence, the mean of x and y is equal to t.

7 0

3 years ago

What is the vertex of the graph of the function f(x) = x² + 8x - 2?

chubhunter [2.5K]

Answer:

(4, -18)

Step-by-step explanation:

First Use this formula for the x -axis -b/2a

-8/2(1) is -4

Then plug in -4 to the equation

(-4)^2+8(-4)-2 = -18

6 0

2 years ago

Identify the three similar right triangles in the given diagram.

irga5000 [103]

Answer:

B. ΔABD, ΔADC, ΔDBC

Step-by-step explanation

Step -1 In ΔABD and ΔADC (from figure).

∠DAB=∠CAD (common in both triangles) ,

∠DBA=∠CDA =90 degree, and

∠BDA=∠DCA (rest angle of the two triangles).

therefore ΔABD similar to ΔADC (by AAA similarity theorem).

Step -2 In ΔDBC and ΔADC (from figure).

∠DCB=∠ACD (common in both triangles) ,

∠DBC=∠ADC =90 degree, and

∠CDB=∠CAD (rest angle of the two triangles).

therefore ΔDBC similar to ΔADC (by AAA similarity theorem).

Step -3 In ΔABD and ΔDBC (from figure).

∠BDA=∠BCD (because , ∠ACD=ADB from stap-1 and ∠ACD=∠BCD from figure) ,

∠DBA=∠CBD =90 degree, and

∠BAC=∠BDC (rest angle of the two triangles).

therefore ΔABD similar to ΔDBC (by AAA similarity theorem).

In the above step- ΔABD similar to ΔADC, ΔDBC similar to ΔADC and ΔABD similar to ΔDBC.

Hence ΔABD, ΔADC, ΔDBC similar to each other in the given figure.

4 0

3 years ago