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11Alexandr11 [23.1K]
2 years ago
8

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

tandard form. 8, -14, and 3 + 9i

Mathematics
2 answers:
Nina [5.8K]2 years ago
6 0

Answer:


Step-by-step explanation:

To start you need to find the factorials of 8, -14, and 3 + 9i.

The factorials of these numbers are:

  8:   x - 8 = 0

 -14:  x + 14 = 0

  3 + 9i: x - 3 - 9i = 0 *    

  3 - 9i: x - 3 + 9i = 0 *        

(If you look in the files it shows how I got these numbers)

Next, you need to multiply the factorials together.

(x - 3 - 9i)(x - 3 + 9i) = x^2 - 6x + 90

Take that and multiply by your next factorial:

(x + 14)(x^2 - 6x + 90) = x^3 + 8x^2 + 6x + 1260

Multiply that by your final factorial and you have you final answer!

(x - 8)(x^3 + 8x^2 + 6x + 1260) = x^4 + 58x^2 + 1212x - 10,080

I hoped this helped!


*When you have 3 + 9i or anything along the lines of that then you need to find the inverse of it. You simply you simply change the sign that goes before the i term. Change <em>3 </em><em>+</em><em> 9i</em> to <em>3 </em><em>- </em><em>9i  </em>


Svetach [21]2 years ago
4 0
First one 80,14 , and second one 12.
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find the mean, median, and mode of the data set. round to the nearest tenth. 7,7,14,15,4,1,7,2,15,9,5
Arisa [49]
Here is the mean, median, and mode:

Mean: 1+2+4+5+7+7+7+9+14+15+15 = 86/11 ≈ 7.82
Median: 7
Mode: 7

To find the mean add up all the numbers and divide by the number of numbers

To find the median you just keep on crossing of numbers left to right until you get the middle number

To find the mode just look at which number is most commonly seen

Hope this helps!
5 0
3 years ago
Read 2 more answers
Simplify: [5×(25)^n+1 - 25 × (5)^2n]/[5×(5)^2n+3 - (25)^n+1​]​
Alekssandra [29.7K]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
2 years ago
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spin [16.1K]

At least means that the number could either equal 6 or be greater than 6.

The inequality would be: n ≥ 6

3 0
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almond37 [142]

Answer: 6(2+2x+1y)

Step-by-step explanation:

i think that is the anwser

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$70 − $66 = $4

Hope this helped.

I got this same exact question in third grade and this was my answer.

3 0
3 years ago
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