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3 years ago

HELP PLEASE!!!

Mathematics

2 answers:

olchik [2.2K]3 years ago

7 0

Answer:

A number or number sentence that doesn't change

Step-by-step explanation:

melisa1 [442]3 years ago

6 0

Answer:

the constant of proportionality k, is the constant value of the ratio of two proportional quantities y and x

Step-by-step explanation:

k = y/x or y= kx

example : the cost of 20 books is rs. 180 how much will 15 books cost ?

a. rs. 125

b. rs. 130

c. rs. 135

d. rs. 140

answer is c. rs. 135

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Which statements can be used to compare the characteristics of the functions? Select three options.

kakasveta [241]

Answer:

Option B and D

Step-by-step explanation:

The complete question is attached

Solution

All f(x) values are not negative hence, option A is incorrect

All g(x) values are the greatest among the three f(x), g(x) and h (x), hence option B is correct

The range of all three functions is different. Hence, option C is incorrect

All h (x) values are negative. Hence, Option D is correct

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3 years ago

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lutik1710 [3]

Answer:

Step-by-step explanation:

solve square root of 3x plus 1 = 4:

D is correct and results in 3x + 1 = 16; after this we subtract 1 from both sides and end up with 3x = 15, or x = 5.

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3 years ago

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A recipe calls for 18 fluid ounces of milk. If Angelica has 2 pints of milk in her refrigerator, does she have enough for the re

natali 33 [55]

Answer:

yes

Step-by-step explanation:

yes

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3 years ago

Read 2 more answers

Question below

Ksivusya [100]

Answer:

$m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]$

Step-by-step explanation:

Calculate the value of m

Given:

$3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]$

Therefore:

$\implies 3=\dfrac{2}{3}m$

$\implies m=3 \times \dfrac{3}{2}$

$\implies m=\dfrac{9}{2}$

Calculate the value of H

Given:

$\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)$