a. The events are mutually exclusive, so

b. For the same reason,

Another way to see this is to use the result from part (a), and the inclusion/exclusion principle:

and the right side reduces to 0.
c. Same as (b),

d. Same as (b),

We can also use the distributivity rule for unions and intersections to write

e. If the
is the complement of
, then by DeMorgan's law,

Answer:
C.) (5,0)
Step-by-step explanation:
You see where the lines cross together. That will be the answer.
Answer:
10!
Step-by-step explanation:
You will need to put 2 half cups to make 1.
So, 10 half cups is equal to 5 cups.
Answer:
1 ten.
Step-by-step explanation:
1 ten = 10 ones/units
Answer:
24-21
Step-by-step explanation:
2×12=24 7×3=21 I started from 2×2 towards 2×12 when I got the answer and I started 7×1 towards 7×3