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Gelneren [198K]
3 years ago
15

When two fair dice are rolled, what is the probability that at least one of the numbers will be even??

Mathematics
1 answer:
netineya [11]3 years ago
4 0
The probability would be 1/4. The probability of rolling an even number on each die is 1/2. Since there are two dice you would multiply the probability of each die together. 1/2*1/2=1/4. The reason you would this is because you could roll two odd numbers that equal an even number such as 3 and 5.
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How do you solve this
arlik [135]
The answer is 1,800, you would multiply 5 by 10 which is 50 then t would be 50 to the 4th power 50 times 4 is 200. then you do the same on the other side 3 time 10 which is 30 to the second power which is 90 than you multiply 200 and 90 because when you have two parentheses next to each other you always multiply but when you do that your answer turns out to be 1,800 
7 0
3 years ago
Jeremy has $120 in his saving account. Katie had $180 in her account. Each week Jeremy adds $14.00 to his account and Katie adds
valkas [14]

Answer:

15 weeks

Step-by-step explanation:

Let the number of weeks = x.

At the end of x weeks,

Jeremy has 120 + 14x,

and Katie has 180 + 10x

We want to know when their amounts are equal.

120 + 14x = 180 + 10x

4x = 60

x = 15

Answer: 15 weeks

8 0
2 years ago
Read 2 more answers
The distance travelled in (m) by a ball dropped from a height are 128/9,32/3,8,6,...
Allushta [10]

Answer: it will trave 56.89 meters before coming to rest.

Step-by-step explanation:

This is a geometric progression since the distance travelled (height) by the ball is reducing by a constant ratio, r. Since the number of times that the ball will bounce is infinite, then we would apply the formula for determining the sum of the terms in a geometric progression to infinity which is expressed as

S = a/(1 - r)

where

S = sum of the distance travelled by the ball

a = initial distance or height of the ball

r = common ratio

From the information given,

a = 128/9

r = (32/3)/(128/9) = 0.75

Therefore,

S = (128/9)/(1 - 0.75) = 56.89 meters

7 0
3 years ago
Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu
Alisiya [41]
Let y=C_1x+C_2x^3=C_1y_1+C_2y_2. Then y_1 and y_2 are two fundamental, linearly independent solution that satisfy

f(x,y_1,{y_1}',{y_1}'')=0
f(x,y_2,{y_2}',{y_2}'')=0

Note that {y_1}'=1, so that x{y_1}'-y_1=0. Adding y'' doesn't change this, since {y_1}''=0.

So if we suppose

f(x,y,y',y'')=y''+xy'-y=0

then substituting y=y_2 would give

6x+x(3x^2)-x^3=6x+2x^3\neq0

To make sure everything cancels out, multiply the second degree term by -\dfrac{x^2}3, so that

f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y

Then if y=y_1+y_2, we get

-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0

as desired. So one possible ODE would be

-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0

(See "Euler-Cauchy equation" for more info)
6 0
3 years ago
Whoever answers correctly gets 45 points
dimulka [17.4K]

m<1=23

m<2=90

m<3=67

m<4=113

m<5=67

the square means it is 90° so 2 is 90°.

all of the angles combined equals 360 so.

360-67-90= 203

since there is a straight line splitting down the middle. m<4=180-67=113

so m<4=113

now you would go 360-67-113-90=90 so

m<1 + m<3 =90

180-90-67=23.

m<1=23

360-67-23-90-113=67

m<3=67

5 0
2 years ago
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