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2 years ago

a chord is drawn 3 cm away from the centre of a circle of radius 5 cm. calculate the length of the chord

Mathematics

1 answer:

lara [203]2 years ago

7 0

Answer:

8 cm

Step-by-step explanation:

the 3 cm line from the chord to the center of a circle is a leg of a right triangle which perpendicularly bisects the chord into two equal halves

draw the hypotenuse of the right triangle from the center of the circle to the endpoint of the chord. This is a radius measuring 5 cm.

find the missing leg of the right triangle

a^2= c^2- b^2

a^2= 25-9

a^2=16

a=4

this is only the measurement of half the chord. To find the full length of the chord multiply by two

4*2=8 cm

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Sveta_85 [38]

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aliya0001 [1]

Answer with explanation:

The coordinates of four points of Quadrilateral ABCD are

A(4, 5), B(–7, –10), C(–4, –9), D(7, 6)

$AB=\sqrt{(4+7)^2+(5+10)^2}\\\\AB=\sqrt{121+225}\\\\AB=\sqrt{346}\\\\BC=\sqrt{(-7+4)^2+(-10+9)^2}\\\\BC=\sqrt{9+1}\\\\BC=\sqrt{10}\\\\CD=\sqrt{(4+7)^2+(5+10)^2}\\\\CD=\sqrt{121+225}\\\\CD=\sqrt{346}\\\\DA=\sqrt{(7-4)^2+(6-5)^2}\\\\DA=\sqrt{9+1}\\\\DA=\sqrt{10}$

Slope between two points is given by

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\m_{1}=\frac{-10-5}{-7-4}\\\\=\frac{-15}{-11}\\\\m_{1}=\frac{15}{11}\\\\m_{2}=\frac{-9+10}{-4+7}\\\\m_{2}=\frac{1}{3}\\\\m_{3}=\frac{6+9}{7+4}\\\\m_{3}=\frac{15}{11}\\\\m_{4}=\frac{6-5}{7-4}\\\\m_{4}=\frac{1}{3}$

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Option A

Yes; The opposite sides are congruent and have the same slope.

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a chord is drawn 3 cm away from the centre of a circle of radius 5 cm. calculate the length of the chord​

a chord is drawn 3 cm away from the centre of a circle of radius 5 cm. calculate the length of the chord