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3 years ago

The rectangle below has an area of 12y^5 square meters and a width of 3y^3 meters

Mathematics

1 answer:

dusya [7]3 years ago

5 0

Answer:

$4y^2$

Step-by-step explanation:

$length \: of \: rectangle \\ = \frac{area}{width} \\ \\ = \frac{12 {y}^{5} }{3 {y}^{3} } \\ \\ = 4 {y}^{5-3} \\ \\ \red{ \bold{ length \: of \: rectangle = 4 {y}^{2} }}$

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Please I really need it ASAP!I'll give you brainliest! please...!!!!

nignag [31]

Answer:

5x+2 = 2x+17

=> 5x-2x = 17-2

=> 3x = 15

=> x = 15/3

=> x = 5

thats my answere

brainlieat me!!!thankyou

#keepitup

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3 years ago

An orange has about 1/4 cup of juice. How many oranges are needed to make 2 1/2 cups of juice? Select all equations that represe

san4es73 [151]

A and D are correct. To understand this, you need to know that this scenario gives us a total (2 1/2 cups) and a part (1/4). When you have these 2 pieces of information you have either a division problem with a total divided into parts (choice D) or you have one part and a totol shown as a multiplication problem (choice A).

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4 years ago

Read 2 more answers

Ms.Groves has trays of paint for students in her art class.each tray has 5 colors.one of the colors is purple.what fraction of t

seropon [69]

So we need to find the fraction of many times does purple show up in 20 trays in which every tray has 5 colors. To find the answer we need to find the overall number of all colors and that is 20 trays * 5 colors and that equals to 100 colors. So purple shows 20 times and 20/100 is 1/5 when we simplify the fraction.

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3 years ago

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Reyesburg Corporation is contemplating using a new, more expensive glue in the construction of its laminated veneer lumber. Of i

Leokris [45]

Answer:

The mean carrying load of the beams tested is 908.7 pounds per square foot

Step-by-step explanation:

1. Data class 1: 860-879

Midpoint 1: M1=(860+879)/2=1,739/2→M1=869.5

Number of values in data class 1: n1=2

2. Data class 2: 880-899

Midpoint 2: M2=(880+899)/2=1,779/2→M2=889.5

Number of values in data class 2: n2=5

3. Data class 3: 900-919

Midpoint 3: M3=(900+919)/2=1,819/2→M3=909.5

Number of values in data class 3: n3=10

4. Data class 4: 920-939

Midpoint 4: M4=(920+939)/2=1,859/2→M4=929.5

Number of values in data class 4: n4=6

5. Data class 5: 940-959

Midpoint 5: M5=(940+959)/2=1,899/2→M5=949.5

Number of values in data class 5: n5=1

Mean=Sum(Mi*ni)/Sum(ni)

Mean=(M1*n1+M2*n2+M3*n3+M4*n4+M5*n5)/(n1+n2+n3+n4+n5)

Mean=(869.5*2+889.5*5+909.5*10+929.5*6+949.5*1)/(2+5+10+6+1)

Mean=(1,739+4,447.5+9,095+5,577+949.5)/(24)

Mean=(21,808)/(24)

Mean=908.6666666

Rounding to one decimal place:

Mean=908.7

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4 years ago

Help me plsss the photo is down fast

kiruha [24]

Answer:

<h2>Option B:</h2><h2> $\frac{1}{5}$ </h2>

Step-by-step explanation:

Given,

Number of numbers of each side of the cube

= 4, 5, 6, 7, 8 and 9

= 6 numbers

Number of sides of cube having the number 5

= 1

Therefore, 

Probability of getting a side of the cube of no. 5 is

$= \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: possible \: outcomes}$

$= \frac{1}{6} (ans) \: (option \: B)$

8 0

3 years ago