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Komok [63]
3 years ago
15

The list price of a product is $52.99. The trade discount is $8.00. The net price of this product is

Mathematics
1 answer:
Paladinen [302]3 years ago
4 0
If one of the answers is close to 33.50 then it’s that
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8 0
3 years ago
How many solutions does the system of equations have?
omeli [17]

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7 0
3 years ago
Mallory took out a loan for $1500. She paid the loan back in 1 year with 7% simple interest. How much did Mallory pay in total?
romanna [79]

Answer:

$1605

Step-by-step explanation:

Because this is simple interest, you can convert the 7% into a decimal

Because she payed an EXTRA 7% she payed 107% total

107% is the equivalent to 1.07

By multiplying 1500 x 1.07 = 1605

6 0
2 years ago
Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−5t
Elan Coil [88]

Answer:

x = 1 - 5t

y = t

z = 1 - 5t

Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

We have x = e^(-5t)cos5t

at t = 1, x = e^(-5)cos5

at t = 0, x = 1

y = e^(-5t)sin5t

at t = 1, y = e^(-5)sin5

at t = 0, y = 0

z = e^(-5t)

at t = 1, z = e^(-5)

at t = 0, z = 1

Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

In vector notation, the curve

r(t) = xi + yj + zk

= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k

r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k

r'(0) = -5i + j - 5k

is a vector tangent at the point.

We get the parametric equation from this.

x = x(0) + tx'(0)

= 1 - 5t

y = y(0) + ty'(0)

= t

z = z(0) + tz'(0)

= 1 - 5t

8 0
3 years ago
3. (03.01)<br> Which expression is equivalent to 3(5 + 6)?<br> 8+9<br> 8 + 6<br> 15 + 18<br> 15 + 6
Afina-wow [57]

Answer:tytgh

Step-by-step explanation:

8 0
3 years ago
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