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3 years ago

The list price of a product is $52.99. The trade discount is $8.00. The net price of this product is

Mathematics

1 answer:

Paladinen [302]3 years ago

4 0

If one of the answers is close to 33.50 then it’s that

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In ΔGHI, the measure of ∠I=90°, the measure of ∠G=62°, and GH = 96 feet. Find the length of IG to the nearest tenth of a foot.

alexandr402 [8]

Answer:

45.1feet

Step-by-step explanation:

Given the following

∠I=90°

∠G=62°, and

GH = 96 feet = Hypotenuse

Required

IG = Adjacent side

Using the SOH CAH TOA identity

Cos theta = Adj/hyp

Cos 62 =IG/96

IG = 96cos62

IG = 96(0.4695)

IG = 45.1feet

Hence the length of IG to the nearest tenth is 45.1feet

6 0

3 years ago

Read 2 more answers

Brainliest if correct

Bad White [126]

Answer:

(-2,11) (0,3) (2,-5) (4,-13)

Step-by-step explanation:

used desmos calculator

8 0

2 years ago

Read 2 more answers

Plz tell me someone know how to do this!! I'll mark brainliest

anygoal [31]

Answer:

It would be the second option

Step-by-step explanation:

z:28 is the ratio of the shorter triangle's side to the larger triangle's side, so is 27:45.

5 0

3 years ago

Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi

Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables X and Y is:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

The formula to compute covariance is:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

The formula to compute the variances are:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}$

Consider the table attached below.

Compute the covariance as follows:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

$=(5\times 165)-(30\times 25)\\=75$

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50$

Compute the correlation coefficient as follows:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

$=\frac{75}{\sqrt{230\times 50}}$

$=0.69937\\\approx0.70$

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0

3 years ago

Use the exterior angle theorem to find the value of x in the triangle below.

Arisa [49]

Answer:

Option A

Step-by-step explanation:

By using the definition of an exterior angle of a triangle,

"Measure of the exterior angle of a triangle is equal to the sum of measures of the opposite interior angles"

m∠STP = m∠SWT + m∠STW

Substitute the measures of the angles from the picture attached,

15x = (7x + 1) + (7x + 6)

15x = (7x + 7x) + (1 + 6)

15x = 14x + 7

15x - 14x = 7

x = 7

Therefore, Option A will be the correct option.

7 0

3 years ago