All categories

3 years ago

-g + 2(3 + g) = -419 + 1) What is the solution

Mathematics

2 answers:

kkurt [141]3 years ago

8 0

Answer: g=-424

Step-by-step explanation:

Given

-g+2(3+g)=-419+1

Expand parenthesis

-g+6+2g=-419+1

Combine like terms

g+6=-418

Subtract 6 on both sides

g+6-6=-418-6

g=-424

Hope this helps!! :)

Please let me know if you have any questions

kompoz [17]3 years ago

7 0

Answer:

Step-by-step explanation:

−

424

You might be interested in

How do you write 4.40 × 10^3 in standard form?

Sindrei [870]

Answer:

4400 is the answer

Step-by-step explanation: You move the decimal point to the right 3 spaces. If it was 10^-3 you would move the decimal point to the left 3 spaces.

8 0

3 years ago

Simplify (-7x+5)-(2x^2-8x+6) in standard form

Zarrin [17]

Answer: -2x² - 15x + 11

Step-by-step explanation:

8 0

2 years ago

Joshua bought a variety of peppers at the market.

lys-0071 [83]

The answer is 9.92 pounds

5 0

3 years ago

I NEED HELP SOMEONE ASAP

Dvinal [7]

Answer: x⁴y²⁰

Step-by-step explanation: Distribute the exponent ⁴ over the parentheses

(x y⁴)⁴ becomes x⁴y¹⁶ (multiply exponents)

then take the 4th root of y¹⁶ (divide the exponent of the radicand by the index) ⁴√y¹⁶ becomes y⁴

Then multiply the factors. Add exponents

x⁴y¹⁶ * y⁴ becomes x⁴y²⁰

8 0

2 years ago

I need help solving this trig problem w/ identites.

Charra [1.4K]

$\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\\\
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\qquad \qquad sec(\theta)=\cfrac{1}{cos(\theta)}
\\\\
-------------------------------$

$\bf \cfrac{1}{sin(x)-1}+\cfrac{1}{sin(x)+1}\implies \cfrac{sin(x)+1~~+~~sin(x)-1}{[sin(x)-1][sin(x)+1]}
\\\\\\
\cfrac{2sin(x)}{\stackrel{\textit{difference of squares}}{sin^2(x)-1^2}}\implies \cfrac{2sin(x)}{sin^2(x)-1}\implies \cfrac{2sin(x)}{-[~1-sin^2(x)~]}
\\\\\\
\cfrac{2sin(x)}{-[cos^2(x)]}\implies -2\cdot \cfrac{sin(x)}{cos(x)}\cdot \cfrac{1}{cos(x)}\implies -2tan(x)sec(x)$

3 0

3 years ago