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densk [106]
3 years ago
8

I'll give you brainliest if you answer! All I need is help with number 15!

Mathematics
1 answer:
Sergio039 [100]3 years ago
6 0

Answer:

120 minutes

Step-by-step explanation:

The lowest number that all three trains times can evenly go into is 120.  60 is not divisible by 8, but 120 is.  So is 12 and 10, so 120.

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Erin buys a bag of peanuts that weighs 3/4 of a pound.later that week the bag is 2/3 full how much does the back of peanuts weig
nasty-shy [4]

The answer is 1/2lbs, here's how.


3/4x2/3=6/12 reduced to 1/2lbs.

4 0
3 years ago
4
Paraphin [41]

Answer:

24

Step-by-step explanation:

Hope this helps have a good day

3 0
3 years ago
Joey’s parents told him that for every 3 hours of chores he completes, they would give him $11for his allowance. His friend Sara
podryga [215]

150 ÷ 20 = 7.5 minutes per 1 mile

7.5 x 6 = 45 minutes

7.5 + 7.5 = 15 minutes or 2 miles in 15

60 ÷ 7.5 = 8 mph

mpm = 7.5

90 ÷ 5 = $18 per hour

18 x 8 = $144

18 x 3 = 54 (close to $60)

Step-by-step explanation:

hope this helps

4 0
3 years ago
Read 2 more answers
Carl bought 24 daisies and roses. Daisies cost $0.25 each and roses cost $0.90 each. If
yuradex [85]

Answer:

Roses= $8.4

Daises= $15.6

Step-by-step explanation:

Let represent the daises and let r represent d roses

r + d= 24....equation 1

0.25r + 0.90d= 16.40.......equation 2

r= 25-d

Substitute 25-d for r in equation 2

0.25(25-d) + 0.90d= 16.40

6.25-0.25d+0.90d= 16.40

6.25+0.65d= 16.40

0.65d= 16.40-6.25

0.65d= 10.15

d= 10.15/0.65

d = 15.6

Sub 15.6 for d in equation 1

r+d= 24

r+15.6= 24

r= 24-15.6

= 8.4

Price of daises is $15.6

Roses is $8.4

4 0
3 years ago
Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and
uysha [10]

Answer:

\frac{x^{2}}{36} - \frac{y^{2}}{64}=1

Step-by-step explanation:

Given an hyperbola with the following conditions:

  • Foci at (-10,0) and (10,0)
  • x-intercept +/- 6;

The following holds:

  • The center is midway between the foci, so the center must be at (h, k) = (0, 0).
  • The foci are 10 units to either side of the center, so c = 10 and c^2 = 100
  • The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

Since the intercepts are 6 units to either side of the center, then a = 6 and a^2 = 36.

Then, a^2+b^2=c^2\\b^2=100-36=64

Therefore, substituting a^2 = 36. and b^2=64 into the standard form

\frac{x^{2}}{a^2} - \frac{y^{2}}{b^2}=1\\We \: have:\\ \dfrac{x^{2}}{36} - \dfrac{y^{2}}{64}=1

4 0
3 years ago
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