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Verizon [17]
3 years ago
10

Sameena buys x packets of batteries and y boxes of batteries write down and expression, in terms of x and y, for the total numbe

r of batteries sameena buys
Mathematics
1 answer:
shusha [124]3 years ago
3 0

Answer:

4x plus 20y

Step-by-step explanation:

4 times x  plus 20xy

4x plus 20y

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What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve.
lapo4ka [179]

Consider the equation x^6+6x^3+5=0.

First, you can use the substitution t=x^3, then x^6=(x^3)^2=t^2 and equation becomes t^2+6t+5=0. This equation is quadratic, so

D=6^2-4\cdot 5\cdot 1=36-20=16=4^2,\ \sqrt{D}=4,\\ \\ t_{1,2}=\dfrac{-6\pm 4}{2} =-5,-1.

Then you can factor this equation:

(t+5)(t+1)=0.

Use the made substitution again:

(x^3+5)(x^3+1)=0.

You have in each brackets the expression like a^3+b^3 that is equal to (a+b)(a^2-ab+b^2). Thus,

x^3+5=(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25}) ,\\x^3+1=(x+1)(x^2-x+1)

and the equation is

(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25})(x+1)(x^2-x+1)=0.

Here x_1=-\sqrt[3]{5} , x_2=-1 and you can sheck whether quadratic trinomials have real roots:

1. D_1=(-\sqrt[3]{5}) ^2-4\cdot \sqrt[3]{25}=\sqrt[3]{25} -4\sqrt[3]{25} =-3\sqrt[3]{25}.

2. D_2=(-1)^2-4\cdot 1=1-4=-3.

This means that quadratic trinomials don't have real roots.

Answer: x_1=-\sqrt[3]{5} , x_2=-1

If you need complex roots, then

x_{3,4}=\dfrac{\sqrt[3]{5}\pm i\sqrt{3\sqrt[3]{25}}}{2}   ,\\ \\x_{5,6}=\dfrac{1\pm i\sqrt{3}}{2}.

6 0
4 years ago
X-(-10)=-20 what is the answere?
MissTica

Answer:

x = -30

Step-by-step explanation:

x - (-10) = -20

Subtracting a negative is adding

x+10 = -20

Subtract 10 from each side to isolate  x

x+10-10 = -20-10

x = -30

8 0
3 years ago
Factor this expression completely.<br> X^2-2x+24
pshichka [43]
There is no solutions, I think you got the signs mixed up.
7 0
3 years ago
Read 2 more answers
What is 75 minutes to ten hours in ratio and simplest form
Arada [10]

Answer:

1:8

Step-by-step explanation:

75min/10hr

10*60=600

75/600

1/8


7 0
3 years ago
Find the area of the shaded region in this figure.
stealth61 [152]

Answer:

B) 190 cm^2

Step-by-step explanation:

Im pretty sure all you gotta do is

20x10 which is 200 then do 5x2

which is 10 and you minus 10 from 200

Please correct me if im wrong here

I dont really remember doing these

6 0
2 years ago
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