Answer:
4x10=40 =40cm^2
Step-by-step explanation:
9514 1404 393
Answer:
0
Step-by-step explanation:
If a=b, you are asking for a whole number c such that ...
c = √(a² +a²) = a√2
If 'a' is a whole number, the only whole numbers that satisfy this equation are ...
c = 0 and a = 0.
0 = 0×√2
The lowest whole number c such that c = √(a²+b²) and a=b=whole number is zero.
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√2 is irrational, so there cannot be two non-zero whole numbers such that c/a=√2.
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<em>Additional comment</em>
If you allow 'a' to be irrational, then you can choose any value of 'c' that you like. Whole numbers begin at 0, so 0 is the lowest possible value of 'c'. If you don't like that one, you can choose c=1, which makes a=(√2)/2 ≈ 0.707, an irrational number. The problem statement here puts no restrictions on the values of 'a' and 'b'.
If a, b and c are the lengths of the sides of a triangle then
if a ≤ b ≤ c, then a + b > c.
1. a ≤ 3 ≤ 8 then a + 3 > 8 → a > 8 - 3 → a > 5 FALSE, because a ≤ 3.
2. 3 ≤ a ≤ 8 then 3 + a > 8 → a > 5 therefore 5 < a ≤ 8
3. 3 ≤ 8 ≤ a then 3 + 8 > a → 11 > a → a < 11 therefore 8 ≤ a < 11.
<h3>Answer: 5 < a < 11 → S = (5, 11)</h3>
Answer:
(3x + 10)(2x + 1)
Step-by-step explanation:
Factor by grouping: 6x2 + 3x + 20x + 10.
This is a polynomial written with four terms that don't have a single common factor among them. However, the first two terms have a common factor (3x), and the last two terms have a common factor (10). This situation doesn't answer all of our wildest factoring dreams, but we'll take it.
By pulling out the common factors for each pair of terms, we can rewrite the original polynomial like this:
3x(2x + 1) + 10(2x + 1)
These two terms now have a common factor of (2x + 1). Seems like we should be able to do something with that information, don't you think? In fact, we can pull out this common factor and rewrite the polynomial again:(3x + 10)(2x + 1)
100tenths/tens because 1 ten x 1 ten is like 10x10 wich equals 100
