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3 years ago

Pls I need help it’s a test

Mathematics

2 answers:

kondaur [170]3 years ago

6 0

I think answer should be A.yes

Alborosie3 years ago

5 0

Answer:

<h2>not a function</h2>

Step-by-step explanation:

vertical line test: if it intersects at more than one point, it is not a function. If it intersects once, it is a function

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Let f(x) = 4x - 5 and g(x) = 3x + 7. Find f(x) + g(x) and state its domain.

dusya [7]

Answer:

2nd option

Step-by-step explanation:

f(x) + g(x)

= 4x - 5 + 3x + 7 ← collect like terms

= 7x + 2

domain is all real numbers

4 0

3 years ago

For every person who has the flue, there are 6 people who have have only flu-like symptoms. If doctor sees 40 patients, determin

nasty-shy [4]

Hello! To solve this question, you'll need to set up a ratio to represent this problem. If there are 6 people who have flu-like systems for every 1 person who has the flu, the ratio would be 6:1. Use this ratio to find the number of patients with only flu-like symptoms.
6 (flu-like symptoms) : 1 (flu)
12:2
18:3
24:4
30:5
36:6
There would be approximately between 30-36 patients with only flu-like systems. Hope this helps! :)

3 0

3 years ago

Easy question!!!! Find the missing length indicated.

Galina-37 [17]

Answer:

is it 3?<em><u> </u></em>(jk)<em><u>it is42</u></em>

Step-by-step explanation:

3 0

3 years ago

HELP PLEASE!!!!!!!!!!!!!!!!!!!! I NEED IT ASAP!!!!!!!!!

FinnZ [79.3K]

I hope this helpssss

4 0

2 years ago

Read 2 more answers

Find f. (Use C for the constant of the first antiderivative and D for the constant of the second antiderivative.)

sashaice [31]

Answer:

$f(x) = x^3 -sinx +Cx+D$

Step-by-step explanation:

Given that:

$f ''(x)= 6x +sinx$

We are given the 2nd derivative of a function f(x) and we need to find f(x) from that.

We will have to integrate it twice to find the value of f(x).

Let us have a look at the basic formula of integration that we will use in the solution:

$1.\ \int {(a\pm b)} \, dx =\int {a} \, dx + \int {b} \, dx \\2.\ \int {x^n} \, dx = \dfrac{x^{n+1}}{n+1}+C\\3.\ \int {sinx} \, dx = -cosx+C\\4.\ \int {cosx} \, dx = sinx+C$

$\int\ {f''(x)} \, dx =\int\ {(6x +sinx)} \, dx \\\Rightarrow \int\ {6x} \, dx + \int\ {sinx} \, dx \\\\\Rightarrow 6\dfrac{x^2}{2} -cosx +C\\\Rightarrow 3{x^2} -cosx +C\\\Rightarrow f'(x)=3{x^2} -cosx +C\\$

Now, integrating it again to find f(x):

$f(x) =\int {f'(x)} \, dx =\int{(3{x^2} -cosx +C)} \, dx \\\Rightarrow \int{3{x^2}} \, dx -\int{cosx} \, dx +\int{C} \, dx\\\Rightarrow 3\times \dfrac{x^3}{3} -sinx +Cx+D\\\Rightarrow x^3 -sinx +Cx+D\\\\\therefore f(x) = x^3 -sinx +Cx+D$

5 0

4 years ago