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Allisa [31]
3 years ago
10

What is the solution to the equation?t

Mathematics
1 answer:
Kisachek [45]3 years ago
3 0

t(9-1)=5\cdot9-5\cdot1\\\\t(9-1)=5(9-1)\to\boxed{t=5}\to\boxed{D.\ 5}

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Will mark brainliest...
morpeh [17]

I can help you! I know the answer but cant type it here sorry! You should try the app Photo Math :) it would give u the answer w steps.

3 0
3 years ago
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The perimeter of a rectangle is 38 in. The width
Alex_Xolod [135]

Good evening ,

______

Answer:

w=6.5in

___________________

Step-by-step explanation:

L : length

w : width

p : perimeter

38=2L+2w

38 =2(w+6)+2w

38 = 4w+12

38-12=4w

26=4w

26/4=w

w=6.5 in.

:)

8 0
3 years ago
What is the equation in slope-intercept form that passes through the points (-4, 47) and (2, -16)?
Whitepunk [10]

Answer:

y = 10.5x - 37

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

Equality Properties

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-4, 47)

Point (2, -16)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{-16-47}{2+4}
  2. Subtract/Add:               m=\frac{63}{6}
  3. Simplify:                        m=\frac{21}{2}

<u>Step 3: Find y-intercept </u><em><u>b</u></em>

  1. Define:                    y = 21/2x + b
  2. Substitute:              -16 = 21/2(2) + b
  3. Multiply:                  -16 = 21 + b
  4. Isolate <em>b</em>:                 -37 = b
  5. Rewrite:                   b = -37

<u>Step 4: Write linear equation</u>

<em>Combine all parts.</em>

y = 21/2x - 37

y = 10.5x - 37

And we have our final answer!

5 0
3 years ago
6. Solve.<br> (1 point)<br> 5x + 17 &gt; 7
kakasveta [241]

Answer:

x > -2

Step-by-step explanation:

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4 0
3 years ago
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Find the general solution of the following equation: y'(t) = 3y -5
Anton [14]

Answer:

The general solution of the equation is y = \frac{A}{3}e^{3t} + 5

Step-by-step explanation:

Since the differential equation is given as y'(t) = 3y -5

The differential equation is re-written as

dy/dt = 3y - 5

separating the variables, we have

dy/(3y - 5) = dt

dy/(3y - 5) = dt

integrating both sides, we have

∫dy/(3y - 5) = ∫dt

∫3dy/[3(3y - 5)] = ∫dt

(1/3)∫3dy/(3y - 5) = ∫dt

(1/3)㏑(3y - 5) = t + C

㏑(3y - 5) = 3t + 3C

taking exponents of both sides, we have

exp[㏑(3y - 5)] = exp(3t + 3C)

3y - 5 = e^{3t}e^{3C}        

3y - 5 = Ae^{3t}                A = e^{3C}

3y = Ae^{3t} + 5    

dividing through by 3, we have

y = \frac{A}{3}e^{3t} + 5

So, the general solution of the equation is y = \frac{A}{3}e^{3t} + 5

3 0
4 years ago
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