W = 27
1 + 1/3L = w
1 + 1/3L = 27
1/3L = 26
L = 78
i am a mathematics teacher. if anything to ask please pm me
- 1 3/5= -8/5 ( Multiply the denominator and whole number ) -1*5= -5 -3= -8
-8/5 ÷ -5/6
-8/5*-6/5 ( whenever dividing flip over the second fraction )
=48/25 ( whenever multiplying - negative and - negative = + positive number
48/25= 1 23/25
Answer :48/25 or 1 23/25
2.5 kilograms is how much i dont think so = 51/51 = 1
Answer:
The Facility cost for each spark plug is $1.4.
Step-by-step explanation:
Given:
Mark up cost = 25%
Charges for each spark plugs for customers = $1.75
We need to find the cost of each spark plug for the facility.
Solution:
Let the Facility cost of each spark plug be 'x'.
So we can say that;
Markup cost = ![25\% \times x= \frac{25}{100}x =0.25x](https://tex.z-dn.net/?f=25%5C%25%20%5Ctimes%20x%3D%20%5Cfrac%7B25%7D%7B100%7Dx%20%3D0.25x)
So we can say that;
Facility cost of each spark plus the Markup cost is equal to cost facilty charges for customer.
framing in equation form we get;
![x+0.25x =1.75\\\\1.25x =1.75](https://tex.z-dn.net/?f=x%2B0.25x%20%3D1.75%5C%5C%5C%5C1.25x%20%3D1.75)
Dividing both side by 1.25 we get;
![\frac{1.25x}{1.25}=\frac{1.75}{1.25}\\\\x= \$1.4](https://tex.z-dn.net/?f=%5Cfrac%7B1.25x%7D%7B1.25%7D%3D%5Cfrac%7B1.75%7D%7B1.25%7D%5C%5C%5C%5Cx%3D%20%5C%241.4)
Hence the Facility cost for each spark plug is $1.4.