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2 years ago

10

Which does not apply?

1 answer:

Assoli18 [71]2 years ago

4 0

Answer:

deez nuțs

Step-by-step explanation:

got em

the answet is b.

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Put these numbers in order from least to greatest.<br> -1, 21/28, -22/25

jek_recluse [69]

Answer:

-22/55,-1,21/28

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the sign of 3 x y 3xy3, x, y when x > 0 x>0x, is greater than, 0 and y < 0 y<0

Colt1911 [192]

Answer:

The sign is negative

Step-by-step explanation:

Given

$Expression = 3xy$

$x > 0$

$y$

Required

Determine the sign

The expression can be split into 3 factors

$(3) (x) (y)$

If x > 0 then x is positive and If y < 0 then y is negative

So, the expression becomes:

$(+3) (+x) (-y)$

<em />

Leave only signs

$(+) (+) (-)$

$+ * + = -$

So, we have:

$(+*+) (-)$

$(+) (-)$

$+ * - = -$

So, we have:

$(+) (-) = -$

<em>Hence, the sign of the expression is negative</em>

<em></em>

Take for instance;

$x = 2$

$y = -4$

The expression would be:

$3 *2 * - 4 =-24$ -- negative

4 0

3 years ago

a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream

Nonamiya [84]

the coordinates where the bridges must be built is $(3,-6)$ and $(6,3)$ .

<u>Step-by-step explanation:</u>

Here we have , a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream at point A and then again at point B. Bridges must be built at those points.We need to find Identify the coordinates where the bridges must be built. Let's find out:

Basically we need to find values of x for which f(x) = g(x) :

⇒ $f(x)-g(x)=0$

⇒ $3x^2- 24x + 39-(3x - 15 ) =0$

⇒ $3x^2- 24x + 39-3x + 15 =0$

⇒ $3x^2- 27x + 54 =0$

⇒ $x^2- 9x + 18 =0$

⇒ $x^2- 6x-3x + 18 =0$

⇒ $x(x- 6)-3(x - 6) =0$

⇒ $(x-3)(x- 6) =0$

⇒ $x=3 , x=6$

Value of g(x) at x = 3 : y=3x -15 = 3(3)-15 = -6

Value of g(x) at x = 6 : y=3x -15 = 3(6)-15 = 3

Therefore , the coordinates where the bridges must be built is $(3,-6)$ and $(6,3)$ .

7 0

3 years ago

A triangle has vertices A(1, 1), B(2, 4), and C(4, 2). Line p is parallel to side AB and contains point C.

kenny6666 [7]

Answer:

$p:y = 3x-10$

Step-by-step explanation:

We are given the following in the question:

A(1, 1), B(2, 4), C(4, 2)

i) Slope of AB

$A(1, 1), B(2, 4)\\\\m = \dfrac{y_2-y_1}{x_2-x_1}\\\\m = \dfrac{4-1}{2-1}=3$

Thus, slope of AB is 3.

ii) Point slope form

The point slope form of a line can be written as:

$y - y_1 = m(x - x_1)$

The point intercept form of line can be written as:

$y = mx + c$

The line is parallel to AB and contains point C(4, 2). Since line p is parallel to AB, line p will have the same slope as line AB

Putting values, we get,

$y - 2 = 3(x-4)\\y = 3x-12+2\\y = 3x-10$

which is the required slope intercept equation of line p.

4 0

3 years ago

A credit card company charges 18.6% percent per year interest. Compute the effective annual rate if they compound, (a) annualy,

Darina [25.2K]

Answer:

a) Effective annual rate: 18.6%

b) Effective annual rate: 20.27%

c) Effective annual rate: 20.43%

d) Effective annual rate: 20.44%

Step-by-step explanation:

The effective annual interest rate, if it is not compounded continuously, is given by the formula

$I=C(1+\frac{r}{n})^{nt}-C$

where

<em>C = Amount of the credit granted </em>

<em>r = nominal interest per year </em>

<em>n = compounding frequency </em>

<em>t = the length of time the interest is applied. In this case, 1 year. </em>

In the special case the interest rate is compounded continuously, the interest is given by

$I=Ce^{rt}-C$

(a) Annually

$I=C(1+\frac{0.186}{1})-C=C(1.186)-C=C(1.186-1)=C(0.186)$

The effective annual rate is 18.6%

(b) Monthly

<em>There are 12 months in a year </em>

$I=C(1+\frac{0.186}{12})^{12}-C=C(1.2027)-C=C(0.2027)$

The effective annual rate is 20.27%

(c) Daily

<em>There are 365 days in a year </em>

$I=C(1+\frac{0.186}{365})^{365}-C=C(1.2043)-C=C(0.2043)$

The effective annual rate is 20.43%

(d) Continuously

$I=Ce^{0.186}-C=C(1.2044)-C=C(0.2044)$

The effective annual rate is 20.44%

3 0

2 years ago