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UNO [17]
3 years ago
12

The carnival at the county fair had a special on ride tickets. Lisa paid $20 for 5 ride tickets at the county fair. What was the

price for each ticket? Round your answer to the nearest cent.
Mathematics
1 answer:
nydimaria [60]3 years ago
4 0

Answer:

$4

Step-by-step explanation:

20÷5=4 ............................................

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HELP HELP HELP HELP PLEASE
Lelechka [254]

Answer:

2

Step-by-step explanation:

Following the order of operations as set out in PEMDAS

6² - 36 ÷ 3² × 4 - 18 ( no parenthesis so evaluate exponents )

= 36 - 36 ÷ 9 × 4 - 18 ( multiplication/ division, evaluate from left to right )

= 36 - 4 × 4 - 18

= 36 - 16 - 18

= 20 - 18

= 2

3 0
2 years ago
Read 2 more answers
What is d+15-9/3+5 PLZZZZZ
zloy xaker [14]
D + 15 - 9 / 3 + 5 the answer is : d + 17
3 0
2 years ago
Evaluate. (15+12)2+310⋅5 Enter your answer as a mixed number in simplest form by filling in the boxes. $$
Sedbober [7]

Hey there!

(15+12)(2)+ 310(5)

= 27(2) + 310(5)

= 54 + 1,550

= 1,604

Therefore, your answer is should be: 1,604

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

8 0
3 years ago
How to simplify <br> -6k +7k<br> 12r -8 -12<br> n -10 +9n -3<br> -4x-10x<br> -r -10r
Semmy [17]

Answer:

Solve by adding or subtracting like terms. (Ex. 2k + 4k = 6k; 9 + 7 = 16)

- 6k + 7k = 1k = k

(7 - 6 = 1)

12r - 8 - 12 = 12r - 20

(8 + 12 = 20 but sign is negative) 12r will stay the same because there are no terms with a letter r.

n - 10 + 9n - 3 = 9n + n - 10 - 3 = 10n - 10 - 3 = 10n - 13

(n = 1 so 9 + 1 = 10; 10 + 3 = 13 but negative sign)

- 4x - 10x = 14x

(10 + 4 = 14)

- r - 10r = 11r

(r = 1 so 10 + 1 = 11)

6 0
3 years ago
Please explain with working!!! Find the set of values of x that satisfy the inequality 9x^2-15x&lt;6
Oksi-84 [34.3K]

Answer:

-1/3

Step-by-step explanation:

When solving a quadratic inequality, first solve it normally like you would for a normal quadratic equation. We have:

9x^2-15x

Ignore the less than sign and replace it with an equal sign and solve the quadratic for its zeros:

9x^2-15x=6

Subtract 6 from both sides:

9x^2-15x-6=0

Divide everything by 3:

3x^2-5x-2=0

Factor. Find two numbers that equal (3)(-2)=-6 that add up to -5.

-6 and 1 works. Thus:

3x^2-6x+x-2=0\\3x(x-2)+1(x-2)=0\\(3x+1)(x-2)=0

Find the x using the Zero Product Property:

3x+1=0 \text{ or }x-2=0\\x=-1/3\text{ or }x=2

Now, we need to replace the equal signs with symbols again. To do so, we need to test which symbol to place. Let's do the first zero first.

So, the first zero is:

x=-1/3

Assume that the correct symbol is >. Thus,

x>-1/3

Now, pick any number that is greater than -1/3. I'll pick 0 since it's the easiest. Now, plug 0 back into the very original inequality. If it works, then the sign is correct, if it doesn't, then simply use the opposite one. Therefore:

9x^2-15x

0 is indeed less than six, so our first correct solution is:

x>-1/3

For the second one, do the same thing. We have:

x=2

Assume that the correct symbol is <. Thus:

x

Again, pick any number less than 2. I'm going to use 0. Plug 0 back into the original equation

9x^2-15x

Again, this is correct. Therefore, x<2 is also the correct inequality.

So together, we have:

x>-1/3 \text{ and } x

Together, we can write them as:

-1/3

(Note that we don't need to worry about the "or equal to" part since the original inequality didn't have it.)

6 0
3 years ago
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