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2 years ago

Help me pleaseeeee I need answers

Mathematics

2 answers:

denis23 [38]2 years ago

5 0

Answer:

1002

Step-by-step explanation:

Plug in the values for a and b that you are given.

50(20) - 2(2) + 6 = ?

1000 - 4 + 6 = 1002

Advocard [28]2 years ago

3 0

Answer:66

Step-by-step explanation:

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Work out 12+8÷(9-5) 0.018÷0.06 Express as single fraction 5/7÷2/5

Anettt [7]

Step-by-step explanation:

I don't know if the first set of numbers is all in one set, but I'll do my best to give you an answer.

Really all you need to do is use PEMDAS for the first question.

(Parentheses, exponents, multiply, divide, add, subtract. In that order)

$1 2 + 8 \div (9 - 5) \\ 12 + 8 \div 4 \\ 12 + 2 \\ 14$

Then to simplify that fraction next to it, notice that 0.018 is 3x 0.06.

that's a 3:1 ratio, so it ends up simplifying to this:

$\frac{3}{1}$

Lastly, to solve the division of that fraction. If you divide by a fraction, you multiply whatever it's dividing by its inverse.

So...

$\frac{5}{7} \div \frac{2}{5} \\ \frac{5}{7} \times \frac{5}{2} \\ \frac{25}{14}$

7 0

3 years ago

What is 20/45 simplified

Andre45 [30]

4/9, is your answer.
Both numerator and denominator can go into 5.
20 divided by 5 is 4, 45 divide by 5 is 9.

6 0

3 years ago

Read 2 more answers

Identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given freque

maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals Frequency

100 - 199 24

200 - 299 90

300 - 399 27

400 - 499 1

500 - 599 4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

99.5 - 199.5

199.5 - 299.5

299.5 - 399.5

399.5 - 499.5

499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

$\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{99.5+199.5}{2}\\\\=149.5$

$\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{199.5+299.5}{2}\\\\=249.5$

$\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{299.5+399.5}{2}\\\\=349.5$

$\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{399.5+499.5}{2}\\\\=449.5$

$\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{499.5+599.5}{2}\\\\=549.5$

The number of individuals included in the summary is the sum of all frequencies.

$\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146$

Thus, the number of individuals included in the summary is 146.

3 0

2 years ago

Read 2 more answers

Coterminal angle help

makkiz [27]

Answer: 320

<u>Step-by-step explanation:</u>

Coterminal means it is in the same place on the Unit Circle but with one or more rotations clockwise or counterclockwise.

Note: one rotation is 360°

-760 + 360 = -400

-400 + 360 = -40

-40 + 360 = 320

320 is between 0 and 360 so this is the angle we are looking for!

7 0

2 years ago

Find two consecutive integers whose sum is 9

Vikki [24]

Answer:

choose any1 u want

-6+15

6+3

-28+37

Step-by-step explanation:

-6+15 =9

7 0

2 years ago

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