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Korolek [52]
3 years ago
9

Help me pleaseeeee I need answers

Mathematics
2 answers:
denis23 [38]3 years ago
5 0

Answer:

1002

Step-by-step explanation:

Plug in the values for a and b that you are given.

50(20) - 2(2) + 6 = ?

1000 - 4 + 6 = 1002

Advocard [28]3 years ago
3 0

Answer:66

Step-by-step explanation:

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In the exponential growth function y = 235(1.15)^x, what is the
sweet-ann [11.9K]

Answer: Growth factor will be 0.15 and percent increase will be 15%.

Step-by-step explanation:

Since we have given that

the exponential growth function

y=235(1.15)^x

1) We need to find the growth factor :

As we know the formula for "Compound Interest ":

A=P(1+\frac{r}{100})^x

If we compare the formula with our given equation, we get

1+\frac{r}{100}=1.15\\\\\frac{r}{100}=1.15-1\\\\\frac{r}{100}=0.15\\\\r=0.15\times 100\\\\r=15

So, the growth factor is at the rate of 0.15.

2) Percent increase will be

0.15=\frac{15}{100}\times 100\\\\=15\%

Hence, growth factor will be 0.15 and percent increase will be 15%.

3 0
3 years ago
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE
EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

g(y) = \frac{y-5}{y^2-3y+15}

According to the quotient rule:

d(\frac{f(y)}{h(y)})  = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}

Applying the quotient rule:

g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}

The values for which g'(y) are zero are the critical points:

g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10

The critical values are y = 0 and y = 10.

5 0
3 years ago
The fraction subtracted from 5/3 to get 1 is_____​
siniylev [52]

Answer:

2/3

Step-by-step explanation:

I am not sure

7 0
2 years ago
Read 2 more answers
5. Which of the following is the equation of a line. that passes through the points (0.8) and (6.4)7 Use of
andriy [413]

See in the explanation

<h2>Explanation:</h2>

In this exercise, <em>we have the following points:</em>

(0.8) \\ \\ (6.4)

And <em>the following linear equations:</em>

(1) \ y=-x+8 \\ \\ (2) \ y=\frac{3}{2}x+6 \\ \\ (3) \ y=-\frac{4}{5}x+4 \\ \\ (4) \ y=\frac{1}{2}x+8

When plotting these graphs, we find the following facts:

<h3>For (1):</h3>

We see the graph in the first figure below. The graph only passes through the point (0, 8)

<h3>For (2):</h3>

This is the second graph below. The graph passes neither through point (0, 8) nor (6, 4)

<h3>For (3):</h3>

This is the third graph below. The graph passes neither through point (0, 8) nor (6, 4)

<h3>For (4):</h3>

This is the fourth graph below. The graph only passes through the point (0, 8)

So, <em>there is no any equation of the line that passes through the points (0.8) and (6.4) at the same time.</em>

<em />

<h2>Learn more:</h2>

About lines: brainly.com/question/12169569

#LearnWithBrainly

8 0
3 years ago
Which phrase represents 3p 6/7p-9
sammy [17]
(3p + 6) divided by (79 - 9)
5 0
2 years ago
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