Answer:
3 bits
Explanation:
Given a 4- way set associative cache that has 64 blocks of 16 words.
Therefore, the number of sets cache has:
Now,
Cache data size is 16kB
The number of cache blocks can be calculated as:
Now,
Total sets =
Total sets =
Now,
n = 6
For 15 bit address for the architecture, the bits in tag field is given by:
15 - (6 + 6) = 3 bits
Thus the tag field will have 3 bits