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Anna11 [10]
3 years ago
5

Which of the following is not a hazard a driver might encounter?

Computers and Technology
1 answer:
coldgirl [10]3 years ago
5 0
The answer is c every other one isa hazed
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Previous
KonstantinChe [14]

Answer: Internet service provider

Explanation:

5 0
3 years ago
How do you do this question?
laila [671]

Answer:

(a) 1 to 8

(b) 1 to 6

Explanation:

A "leaf" is a node at the end of a binary tree (in other words, it has no "children").  All other nodes are "non-leaf" nodes.

The smallest number of leaves is 1.  That would be a binary tree that's just a straight line; each node will have only 1 child, until you get to the last node (the leaf).

To find the largest number of leaves, we start drawing a full binary tree.  A complete tree with 15 nodes has 7 non-leaf nodes and 8 leaf nodes.  A full tree with 6 non-leaf nodes can have up to 6 leaf nodes.

6 0
3 years ago
Read 2 more answers
8.
Licemer1 [7]

Answer:

yes

Explanation:

the faster the processor the better the computer loads things and works faster, there's little to no latency depending on the wifi

3 0
3 years ago
When a superclass variable refers to a subclass object and a method is called on that object, the proper implementation is deter
Anni [7]

Answer:

D. Late binding

Explanation:

a. early binding.

b. non-binding.

c. on-time binding.

d. late binding.

The compiler performs a process called binding when an object is assigned to an object variable. The early binding (static binding) refers to compile time binding and late binding (dynamic binding) refers to runtime binding. Another name for late binding is dynamic linkages

It is a computer programming mechanism in which the method being called upon an object or the function being called with arguments is looked up by name at runtime.

When a superclass variable refers to a subclass object and a method is called on that object, the proper implementation is determined at execution time. The process of determining the correct method to call is known as Late Binding.

7 0
3 years ago
Read 2 more answers
Without any knowledge of the key, an attacker with access to an encrypted message and the decryption cipher could try every poss
dsp73
A brute force attack. Ciphers should be sufficiently complex for this to be ever successful.
6 0
4 years ago
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