Question

A bag contains hair ribbons for a spirit rally. The bag contains 9 black ribbons and 6 green ribbons. Lila selects a ribbon at random, then Jessica selects a ribbon at random from the remaining ribbons. What is the probability that Lila selects a black ribbon and Jessica selects a green ribbon? Express your answer as a fraction in simplest form.

Answer 1

Since these are done in order, and without replacement: 

Lila selecting black = 7/12 (7 black ribbons out of 12 ribbons total) 
Jessica *then* selecting a green ribbon = 5/11 ( 5 green ribbons left out of 11 ribbons left) 

Chance of this specific event = (7/12)*(5/11) = 35/132Mike · 6 years ago

Answer 2

Answer:

Option B. $\frac{9}{35}$

Step-by-step explanation:

A bag contains black ribbons = 9

Green ribbons = 6

Total ribbons = 9 + 6 = 15

First Lila selects a ribbon, the probability that Lila selects a black ribbon $P_{1}$ = $\frac{9}{15}$

Then Jessica selects a ribbon without replacement so the probability that Jessica selects green ribbon $P_{2}$ = $\frac{6}{14}$

P = $P_{1}$ × $P_{2}$

P = $\frac{9}{15}$ × $\frac{6}{14}$ = $\frac{54}{210}$ = $\frac{9}{35}$

The probability that Lila selects a black ribbon and Jessica selects a green ribbon is $\frac{9}{35}$.