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s2008m [1.1K]
3 years ago
15

The coordinates are (? , ?).

Mathematics
1 answer:
4vir4ik [10]3 years ago
7 0

Answer:

(1.5,1)

Step-by-step explanation:

The midpoint of G and H is at (2,2).

The midpoint if J and K is (1,0)

The midpoint of the two midpoints is (1.5,1)

You could also i.e. directly ask for the midpoint of H an K, OR, G and J, and you would get the same final result.

(same as in the other post I guess)

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I will make you Brainliest
stepladder [879]

Answer and Step-by-step explanation:

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x\geq -1

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x < 2

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6 0
3 years ago
A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ=0.0
oksian1 [2.3K]
<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

\overline{x}\pm z^* SE                   (1)

, where \overline{x} = sample mean

z* = critical value.

SE = standard error

and SE=\dfrac{\sigma}{\sqrt{n}} , \sigma = population standard deviation.

n= sample size.

As per given , we have

\overline{x}=74.021

\sigma=0.001

n= 15

It is known that ring diameter is normally distributed.

SE=\dfrac{0.001}{\sqrt{15}}=0.000258198889747\approx0.000258199

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 99% two-sided confidence interval on the true mean piston diameter :

74.021\pm (2.576) (0.000258199)     (using (1))

74.021\pm 0.000665120624

74.021\pm 0.000665120624\\\\=(74.021- 0.000665120624,\ 74.021+ 0.000665120624)\\\\=(74.0203348794,\ 74.0216651206)\approx(74.020,\ 74.022)  [Rounded to three decimal places]

∴  A 99% two-sided confidence interval on the true mean piston diameter  = (74.020, 74.022)

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 95% lower confidence bound on the true mean piston diameter:

74.021- (1.96) (0.000258199)    (using (1))

74.021- 0.00050607004=74.02049393\approx74.020 [Rounded to three decimal places]

∴  A 95% lower confidence bound on the true mean piston diameter= 74.020

7 0
3 years ago
F(x)=|x+8| evaluate f(-11)
stealth61 [152]
19:) 
I hope that helped!
7 0
3 years ago
If f(x) = 8x2-5, what is f(-1)
Nikolay [14]

Answer:3

Step-by-step explanation:

Simply plug in -1 for anywhere you see x in the equation so...

8(-1)^2-5

8(1)-5

8-5

3

Hope this helps

4 0
3 years ago
Read 2 more answers
What is the average of 143, 98, and 128
asambeis [7]
Average\ A=\frac{S}{N}\\\\A=\frac{143+98+128}{3}=\frac{369}{3}=123\\\\Average\ of\ these\ numbers\ is\ 123.
8 0
3 years ago
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