The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

1 answer:

7 0

B. No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32

Perimeter = 2(l + w)
Perimeter = 64

Assuming: P = 64; w = 11 ; l = ?
64 = 2(l + 11)
64/2 = l + 11
32 - 11 = l
length = 21.

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