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oksano4ka [1.4K]
3 years ago
12

The graph of y=f(x) is shown below.which point could be used to find f(3).

Mathematics
2 answers:
QveST [7]3 years ago
5 0

Answer:

aa is the repuestos yes ok

tatuchka [14]3 years ago
5 0

Answer:

A

Step-by-step explanation:

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What is the y-intercept of the function f(x)=4 - 5x?<br> -5<br> -4<br> 4<br> 5
pantera1 [17]

Answer:

b = 4

Step-by-step explanation:

Use the slope-intercept form  y = m x + b  to find the y-intercept  b .

8 0
3 years ago
Read 2 more answers
Scott wants to cover his patio with concrete pavers. If the patio is shaped like a trapezoid whose bases are 11 feet and 13 feet
GenaCL600 [577]

<u><em>Answer:</em></u>

Scott will need 168 ft² of pavers to cover his patio

<u><em>Explanation:</em></u>

Scott wants to cover a trapezoid-shaped patio

<u>This means that:</u>

To get the number of square feet of pavers he'll need, we need to get the area of his patio

<u>Area of trapezium id calculated as follows:</u>

Area = \frac{base_{1}+base_{2}}{2} * height

<u>We are given that:</u>

base₁ = 11 ft

base₂ = 13 ft

height = 14 ft

<u>We now substitute with the givens to get the area as follows:</u>

Area = \frac{11+13}{2} * 14 = 168ft^2

<u>This means that:</u>

Scott will need 168 ft² of pavers to cover his patio

Hope this helps :)

5 0
3 years ago
A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 30 ft/s. Its height
Crank

Answer:

a) h = 0.1: \bar v = -11\,\frac{ft}{s}, h = 0.01: \bar v = -10.1\,\frac{ft}{s}, h = 0.001: \bar v = -10\,\frac{ft}{s}, b) The instantaneous velocity of the ball when t = 2\,s is -10 feet per second.

Step-by-step explanation:

a) We know that y = 30\cdot t -10\cdot t^{2} describes the position of the ball, measured in feet, in time, measured in seconds, and the average velocity (\bar v), measured in feet per second, can be done by means of the following definition:

\bar v = \frac{y(2+h)-y(2)}{h}

Where:

y(2) - Position of the ball evaluated at t = 2\,s, measured in feet.

y(2+h) - Position of the ball evaluated at t =(2+h)\,s, measured in feet.

h - Change interval, measured in seconds.

Now, we obtained different average velocities by means of different change intervals:

h = 0.1\,s

y(2) = 30\cdot (2) - 10\cdot (2)^{2}

y (2) = 20\,ft

y(2.1) = 30\cdot (2.1)-10\cdot (2.1)^{2}

y(2.1) = 18.9\,ft

\bar v = \frac{18.9\,ft-20\,ft}{0.1\,s}

\bar v = -11\,\frac{ft}{s}

h = 0.01\,s

y(2) = 30\cdot (2) - 10\cdot (2)^{2}

y (2) = 20\,ft

y(2.01) = 30\cdot (2.01)-10\cdot (2.01)^{2}

y(2.01) = 19.899\,ft

\bar v = \frac{19.899\,ft-20\,ft}{0.01\,s}

\bar v = -10.1\,\frac{ft}{s}

h = 0.001\,s

y(2) = 30\cdot (2) - 10\cdot (2)^{2}

y (2) = 20\,ft

y(2.001) = 30\cdot (2.001)-10\cdot (2.001)^{2}

y(2.001) = 19.99\,ft

\bar v = \frac{19.99\,ft-20\,ft}{0.001\,s}

\bar v = -10\,\frac{ft}{s}

b) The instantaneous velocity when t = 2\,s can be obtained by using the following limit:

v(t) = \lim_{h \to 0} \frac{x(t+h)-x(t)}{h}

v(t) =  \lim_{h \to 0} \frac{30\cdot (t+h)-10\cdot (t+h)^{2}-30\cdot t +10\cdot t^{2}}{h}

v(t) =  \lim_{h \to 0} \frac{30\cdot t +30\cdot h -10\cdot (t^{2}+2\cdot t\cdot h +h^{2})-30\cdot t +10\cdot t^{2}}{h}

v(t) =  \lim_{h \to 0} \frac{30\cdot t +30\cdot h-10\cdot t^{2}-20\cdot t \cdot h-10\cdot h^{2}-30\cdot t +10\cdot t^{2}}{h}

v(t) =  \lim_{h \to 0} \frac{30\cdot h-20\cdot t\cdot h-10\cdot h^{2}}{h}

v(t) =  \lim_{h \to 0} 30-20\cdot t-10\cdot h

v(t) = 30\cdot  \lim_{h \to 0} 1 - 20\cdot t \cdot  \lim_{h \to 0} 1 - 10\cdot  \lim_{h \to 0} h

v(t) = 30-20\cdot t

And we finally evaluate the instantaneous velocity at t = 2\,s:

v(2) = 30-20\cdot (2)

v(2) = -10\,\frac{ft}{s}

The instantaneous velocity of the ball when t = 2\,s is -10 feet per second.

8 0
3 years ago
A.
zhenek [66]

Answer:

640 cm³

Step-by-step explanation:

Each prism has a volume of (4 cm) (4 cm) (20 cm) = 320 cm³.

There are two prisms, so the total volume is 640 cm³.

4 0
3 years ago
I can’t figure this out
zysi [14]

Answer: -1/3 is the correct answer

Step-by-step explanation:

6 0
3 years ago
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