3 years ago

What is the square root of 150 and 136? Thanks :)

Mathematics

1 answer:

algol133 years ago

7 0

The square root of 150 is 12.2474487139. The square root of 136 is 11.6619037897. And your welcome :)

You might be interested in

A principal of $4,570 is placed in an account that earns 4. 5% interest. If the interest is compounded annually, how much money

iVinArrow [24]

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$4570\\ r=rate\to 4.5\%\to \frac{4.5}{100}\dotfill &0.045\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=4570\left(1+\frac{0.045}{1}\right)^{1\cdot 5}\implies A=4570(1.045)^5\implies A\approx 5695.05$

8 0

2 years ago

Please actually help because my anxiety sucks. "Joe is seven years younger than Bill. The sum of their ages is less than 49. At

kherson [118]

Joe is at most 20 and Bill would be at most 27 because it has to be less than 49 combined

5 0

3 years ago

Solve the system of equations by substitution <br> 2x+3y=9 <br> y=x−2

garri49 [273]

so I think u you divide something and you times and then you multiply it

6 0

3 years ago

Read 2 more answers

The surface area, S, of a sphere of radius r feet is S = S(r) = 4πr^2. Find the instantaneous rate of change of the surface area

8090 [49]

Instantaneous rate of change = S'(r) = 8πr
S'(8) = 8π(8) = 64π

Therefore, the instantaneoud rate of change of the <span>surface area with respect to the radius r at r = 8</span> is 64π

7 0

3 years ago

7a-11=-2(3a-1) what is the work and answer

Anni [7]

The work is on the picture attached, but a = 1
Hope this helps!!

3 0

3 years ago