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sasho [114]
3 years ago
10

A circular test track for cars has a circumference of 2.7km . A car travels around the track from the southernmost point to the

northernmost point. What distance does the car travel? (answer 1.35km). Part B !!!!!!!What is the car's displacement from its original position?,
Mathematics
1 answer:
Galina-37 [17]3 years ago
5 0
This problem is about the difference between distance and displacement.
The distance is how many kilometers has the car covered, the displacement is how far from the original point is the car now, and does not depend on the path followed, but it is the shortest path that connects two points.

a) In this part, they ask you for the distance. From the southernmost to the northernmost point of the circumference, the car has traveled half of the circumference, therefore:
distance = circumference ÷ 2 = 2.7km ÷ 2 = 1.35km

b) In this part, you are asked for the displacement, which in this case is the diameter of the circumference:
displacement = diameter = circumference ÷ π = 2.7km ÷ 3.14 = 0.86km = 860m
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Solve the system of equations using substitution. Write the solution as an ordered pair.
IrinaK [193]

Answer:

  (-3, 3)

Step-by-step explanation:

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4 0
3 years ago
50 POINTS
Marina86 [1]

vi is going in the positive direction (up). (That's my choice). a (acceleration) is going in the minus direction (down). The directions could be reversed.

Givens

vi = 160 ft/s

vf = 0 (the rocket stops at the maximum height.)

a = - 9.81 m/s

t = ????

Remark

YOu have 4 parameters between the givens and what you want to solve. Only 1 equation will relate those 4. Always always list your givens with these problems so you can pick the right equation.

Equation

a = (vf - vi)/t

Solve

- 32 = (0 - 160)/t Multiply both sides by t

-32 * t = - 160 Divide by -32

t = - 160/-32

t = 5

You will also need to solve for the height to answer part B

t = 5

vi = 160 m/s

a = - 32

d = ???

d = vi*t + 1/2 a t^2

d = 160*5 + 1/2 * - 32 * 5^2

d = 800 - 400

d = 400 feet

Part B

You are at the maximum height. vi is 0 this time because you are starting to descend.

vi = 0

a = 32 m/s^2

d = 400 feet

t = ??

formula

d = vi*t + 1/2 a t^2

400 = 0 + 1/2 * 32 * t^2

400 = 16 * t^2

400/16 = t^2

t^2 = 25

t = 5 sec

The free fall takes the same amount of time to come down as it did to go up. Sort of an amazing result.

6 0
3 years ago
What is cosine ? I really need this answer for my test tomorrow. Please help
Kisachek [45]
Cosine is \frac{adjacent}{hypotenuse} which applies to a right triangle. I hope that helps you.
3 0
3 years ago
Read 2 more answers
Help please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
jarptica [38.1K]

\huge\color{pink}\boxed{\colorbox{Black}{♔︎Answer♔︎}}

x = 2

<em>right</em><em> </em><em>option</em><em> </em><em>is</em><em> </em>(E).

Step-by-step explanation:

f(x) = x³ - 3x² + 12 in interval [-2, 4]

{taking f'(x) by doing derivative of f(x)}

f'(x) = 3x² - 6x

.•. f'(x) = 0

0 = 3x² - 6x

0 = 3x(x - 2)

0 = x - 2

x = 2

4 0
2 years ago
Read 2 more answers
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