Question

Use the method of completing the square to solve x2-8x+7=0

Answer 1

A should be your answer no 100 %

Answer 2

$Solution, solve\:for\:x,\:x^2-8x+7=0\quad :\quad x=7,\:x=1$

Steps:

$Solve\:with\:the\:quadratic\:formula, \mathrm{For\:}\quad a=1,\:b=-8,\:c=7:\quad x_{1,\:2}=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:7}}{2\cdot \:1},$

$x=\frac{-\left(-8\right)+\sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:7}}{2\cdot \:1}:\quad 7$

$x=\frac{-\left(-8\right)-\sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:7}}{2\cdot \:1}:\quad 1$$\mathrm{The\:final\:solutions\:to\:the\:quadratic\:equation\:are:} x=7,\:x=1$

The correct answer is B.