2 years ago

What’s the area of segment (shaded region) PLEASE HELP FAST

Mathematics

1 answer:

Ainat [17]2 years ago

4 0

Answer:

find the area if the sector,then the area of the triangle.After that, Subtract the area of the triangle from the area of the sector

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One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant rate from 8 p.m. to midnight. At mi

Diano4ka-milaya [45]

Let y be the temperature
Let m be the rate of temperature drop in degrees per hour
Let x be the number of hours elapsed since 8PM
The initial temperature (at x = 0) is 0
y = mx
Four hours from 8 PM, the temperature was -16.8 degrees
-16.8 = m(4)
m = -4.2 degrees per hour
At 9PM, one hour will have elapsed.
y = -4.2(1)
y = -4.2 degrees

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3 years ago

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charle [14.2K]

Y intercept is (0,-12), the x-intercept is (4,0)

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3 years ago

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bixtya [17]

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3 years ago

Help please!! i don’t understand this one!

12345 [234]

Answer:

C, D

Step-by-step explanation:

This equation can be solved any of several ways. One that doesn't require much thought is using the quadratic formula.

For ax² +bx +c = 0, the solutions are ...

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In the given equation, a=2, b=11, c=5, so this becomes ...

$x=\dfrac{-11\pm\sqrt{11^2-4\cdot2\cdot5}}{2\cdot2}=\dfrac{-11\pm\sqrt{81}}{4}\\\\x=\dfrac{-11\pm9}{4}=\left\{-\dfrac{20}{4},-\dfrac{2}{4}\right\}=\{-5,-\frac{1}{2}\}$

The solutions are ...

C. x = -5

D. x = -1/2

_____

My personal favorite is using a graphing calculator. The solutions are the x-intercepts of the expression on the left. That is, where its value is zero, as the equation says.

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3 years ago

-3 < 5c + 7 < 22<br> algebra

Alexus [3.1K]

Answer:=

Solution: -2<c<3

Interval Notation: (-2,3)

Step-by-step explanation:

-3<5c+7<22

-3<5c+7 : c>-2

5c+7<22 : c<3

combine the intervals

c>-2 and c<3

-2<c<3

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3 years ago