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madreJ [45]
2 years ago
11

Which ordered pair is a solution of the equation shown? 25 points

Mathematics
2 answers:
Dahasolnce [82]2 years ago
7 0

Answer:

4y-2 / 3

Step-by-step explanation:

mestny [16]2 years ago
3 0
Let’s find the y intercept

set x to zero to get y=3/4(0) +1/2

multiply 3/4 and 0 to get y=1/2

so the x value is 0 and the y value is 1/2

the ordered pair would be (0, 1/2)

there’s others but this is probably the easiest one to find

hope this helped!!
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Men in the age groups of 18-34 years need to be to run a marathon in 3 hours and 10 minutes to qualify for the boston marathon h
igomit [66]
11,400 seconds
You would take 3 hours to minutes which is 180 then add the following 10 minutes and convert it to seconds.

5 0
3 years ago
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Teresa, Pablo, and Felipe have a total of $106 in their wallets. Pablo has 4 times what Felipe has. Teresa has $8 less than Feli
Genrish500 [490]

Answer: Felipe= 106

Teresa=98

Pablo=464

Step-by-step explanation:

Since Pablo has 4 times you do $106x4=464 and Teresa has 8 less so $106-8= $98

7 0
3 years ago
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In list T, consists of 30 positive decimals. None of which are integers. The sum of the 30 decimals is S. The estimated sum of t
Masteriza [31]

Answer: E - S = (-16 and 6)

Step-by-step explanation:1/3 of the 30 decimals in T have an even tenths digit, it follows that 1/3*(30)=10 decimals in T have an even tenths digit.

Hence: Te =list of 10 decimals

Se = sum of all 10 decimals in Te

Ee =estimated sum of all 10 decimals in Te after rounding up.

Remaining 20 decimals in T all have an odd tenths digits.

To =list of this 20 decimals

So = sum of all 20 decimals in To

Eo = estimated sum of 20 decimals in To

Hence,

E = Ee + Eo and S =Se +So, hence:

E-S, =(Ee+Eo) - (Se+So) =(Ee-Se) +(Eo-So)

Ee-Se >10 (0.1)=1

S=10(1.8)+20(1.9) =18+38=56

E=10(2)+20(1)=40

E-S =40-56=-16.

AlsoS=10(1.2)+20(1.1)=34

E=10(2)+20(1)=40

E-S=40-34=6

6 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIEST
DanielleElmas [232]

Option A:

(x-5)^{2}+(y-3)^{2}=16

Solution:

Given data:

Center of the circle is (5, 3).

Radius of the circle = 4

To find the equation of the circle:

The general form of the equation of a circle in centre-radius format is

(x-h)^{2}+(y-k)^{2}=r^{2}

where (h, k) is the centre of the circle and r is the radius of the circle.

Substitute the given values in the equation of a circle formula:

(x-5)^{2}+(y-3)^{2}=4^{2}

(x-5)^{2}+(y-3)^{2}=16

The equation of the given circle is (x-5)^{2}+(y-3)^{2}=16.

Hence Option A is the correct answer.

5 0
3 years ago
Find the surface area of the following figure.
fgiga [73]

Answer:

\boxed{\textsf{\pink{ Hence the TSA of the cuboid is $\sf 32x^2$}}}.

Step-by-step explanation:

A 3D figure is given to us and we need to find the Total Surface area of the 3D figure . So ,

From the cuboid we can see that there are 5 squares in one row on the front face . And there are two rows. So the number of squares on the front face will be 5*2 = 10 .

We know the area of square as ,

\qquad\boxed{\sf Area_{(square)}= side^2}

Hence the area of 10 squares will be 10x² , where x is the side length of each square. Similarly there are 10 squares at the back . Hence their area will be 10x² .

Also there are in total 12 squares sideways 6 on each sides . So their surface area will be 12x² . Hence the total surface area in terms of side of square will be ,

\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies\boxed{\sf TSA_{(cuboid)}= 32x^2}

Now let's find out the TSA in terms of side . So here the lenght of the cuboid is equal to the sum of one of the sides of 5 squares .

\sf\implies 5x = l \\\\\sf\implies x = \dfrac{l}{5} \\\\\qquad\qquad\underline\red{ \sf Similarly \ breadth }\\\\\sf\implies b = 3x  \\\\\sf\implies x = \dfrac{ b}{3}

\rule{200}2

Hence the TSA of cuboid in terms of lenght and breadth is :-

\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies TSA_{(cuboid)}= 20\bigg(\dfrac{l}{5}\bigg)^2+12\bigg(\dfrac{b}{3}\bigg) \\\\\sf\implies TSA_{(cuboid)}= 20\times\dfrac{l^2}{25}+12\times \dfrac{b^2}{9}\\\\\sf\implies \boxed{\red{\sf TSA_{(cuboid)}= \dfrac{4}{5}l^2 +\dfrac{4}{3}b^2 }}

6 0
2 years ago
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