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2 years ago

Which ordered pair is a solution of the equation shown? 25 points

Mathematics

2 answers:

Dahasolnce [82]2 years ago

7 0

Answer:

4y-2 / 3

Step-by-step explanation:

mestny [16]2 years ago

3 0

Let’s find the y intercept

set x to zero to get y=3/4(0) +1/2

multiply 3/4 and 0 to get y=1/2

so the x value is 0 and the y value is 1/2

the ordered pair would be (0, 1/2)

there’s others but this is probably the easiest one to find

hope this helped!!

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BRAINLIEST For the fastest answer<br>Hello I need help on this math question<br><br>

otez555 [7]

Answer:

Here is the answer...hope it helps:)

5 0

2 years ago

Ali takes a full-time position as a makeup artist in Atlanta. Her starting salary is $29,000. Her taxes are 28%. What is her net

malfutka [58]

Answer:

d. $1,740

Step-by-step explanation:

The annual after-tax salary is found by subtracting the tax from the salary. The tax is found by multiplying the tax rate by the salary. The monthly after-tax income is 1/12 of the annual after-tax income.

<h3>steps</h3>

annual tax = 0.28 × $29,000 = $8,120

annual take-home pay = $29,000 -8,120 = $20,880

monthly take-home pay = annual pay / months per year

= $20,880 / 12 = $1,740 . . . . net monthly income

_____

<em>Additional comment</em>

The net pay will be (1 - 0.28) = 0.72 times the nominal salary. The monthly pay will be 1/12 of the annual pay. These combined factors give a monthly net pay of (0.72)(1/12) = 0.06 times the annual pay.

0.06 × $29000 = 6×$290 = $1740

7 0

1 year ago

WILL MARK BRAINLIESTPlease can anyone tell me how to solve this equation and give me the answer i really want to understand this

lisabon 2012 [21]

1) Transform the inequality into equation by replacing "<" or ">" with "=":
-2x - 4 > 8
-2x - 4 = 8
2) Simply solve for x:
-2x - 4 = 8
-2x = 8 + 4
-2x = 12
x = -6
3) Now do the following exactly the same: first, look into the symbol that you have replaced (">" or "<"). Put the same symbol into your answer "x = -6":
x > -6
4) Now, look which symbol was in front of "x" in the original inequality (-2x - 4 = 8). If it is "+" (for example, 4x, 0.01x) leave "x > -6". If it is "-" (for example, -3x, -0.04x) change ">" into "<" or change "<" into ">" (put the opposite symbol).
5) You have -2x in the original inequality - then, in "x > -6" change the symbol into "<". So, your answer will be
x < -6 or the option 1.
Hope this helps!

3 0

3 years ago

Read 2 more answers

The annual inventory cost C for a manufacturer is given below, where Q is the order size when the inventory is replenished. Find

shtirl [24]

Answer:

Change in annual cost is 1.63 (decreasing).

Instantaneous rate of change is 1.65 (decreasing).

Step-by-step explanation:

Given that,

$C=\dfrac{1017000}{Q}+6.8\:Q$

The annual change in cost is given by,

$Change\:in\:C=C\left(348\right)-C\left(347\right)$

Calculate the value of cost at Q = 347 and Q =348 by substituting the value in cost function.

Calculating value of C at Q=347,

$C=\dfrac{1017000}{347}+6.8\left(347\right)$

$C=5290.44$

Calculating value of C at Q=348,

$C=\dfrac{1017000}{348}+6.8\left(348\right)}$

$C= 5288.81$

Substituting the value,

$Change\:in\:C=5288.81-5290.44$

$Change\:in\:C=-1.63$

Negative sign indicate that there is decrease in annual cost when Q is increased from 347 to 348

Therefore, change is annual cost is 1.63 (decreasing).

Instantaneous rate of change is given by the formula,

$f’\left(x\right)=\lim_{h\rightarrow 0}\dfrac{f\left(x+h\right)-f\left(x\right)}{h}$

Rewriting,

$C’\left(Q\right)=\lim_{h\rightarrow 0}\dfrac{C\left(Q+h\right)-C\left(Q\right)}{h}$

Now calculate \dfrac{C\left(Q+h\right) by substituting the value Q+h in cost function,

$C\left(Q+h\right)= \dfrac{1017000}{Q+h}+6.8\left(Q+h\right)$

Therefore,

$C’\left(Q\right)= \lim _{h\to 0}\:\dfrac{\dfrac{1017000}{Q+h}+6.8\left(Q+h\right)-\left(\dfrac{1017000}{Q}+6.8Q\right)}{h}$

By using distributive law,

$C’\left(Q\right) = \lim _{h\to 0}\:\dfrac{\dfrac{1017000}{Q+h}+6.8Q+6.8h-\dfrac{1017000}{Q}-6.8Q}{h}$

Cancelling out common factors,

$C’\left(Q\right) = \lim _{h\to 0}\:\dfrac{\dfrac{1017000}{Q+h}-\dfrac{1017000}{Q}+6.8h}{h}$

Now, LCD of $\left(Q+h\right)$ and $Q$ is $Q(Q+h)$ . So multiplying first term by $Q$ and second term by

Therefore,

$C’\left(Q\right) = \lim _{h\to 0}\:\dfrac{\dfrac{1017000}{Q+h}\times\dfrac{Q}{Q}-\dfrac{1017000}{Q}\times\dfrac{Q+h}{Q+h}+6.8h}{h}$

Simplifying,

$C’\left(Q\right) = \lim _{h\to 0}\:\dfrac{\dfrac{1017000Q}{\left(Q+h\right)\left(Q\right)}-\dfrac{1017000\left(Q+h\right)}{Q\left(Q+h\right)}+6.8h}{h}$