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madreJ [45]
2 years ago
11

Which ordered pair is a solution of the equation shown? 25 points

Mathematics
2 answers:
Dahasolnce [82]2 years ago
7 0

Answer:

4y-2 / 3

Step-by-step explanation:

mestny [16]2 years ago
3 0
Let’s find the y intercept

set x to zero to get y=3/4(0) +1/2

multiply 3/4 and 0 to get y=1/2

so the x value is 0 and the y value is 1/2

the ordered pair would be (0, 1/2)

there’s others but this is probably the easiest one to find

hope this helped!!
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Rhonda's age decreased by 18 is 72.
alukav5142 [94]

Answer:

72-18=54

Step-by-step explanation:

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5 0
2 years ago
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Can it be solve pq(r²+1)-r(p²+q²)
ivann1987 [24]

Answer:

pqr²+pr-rp²+rq²

Step-by-step explanation:

pq(r²+1)-r(p²+q²)

pqr²+pr-rp²+rq²

3 0
1 year ago
A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the number of cakes sold per
HACTEHA [7]

Answer:

A) Revenue function = R(x) = (580x - 10x²)

Marginal Revenue function = (580 - 20x)

B) Fixed Cost = 900

Marginal Cost function = (300 + 50x)

C) Profit function = P(x) = (-35x² + 280x - 900)

D) The quantity that maximizes profit = 4

Step-by-step explanation:

Given,

The Price function for the cake = p = 580 - 10x

where x = number of cakes sold per day.

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

where x = number of cakes sold per day.

Please note that all the calculations and functions obtained are done on a per day basis.

A) Find the revenue and marginal revenue functions [Hint: revenue is price multiplied by quantity i.e. revenue = price × quantity]

Revenue = R(x) = price × quantity = p × x

= (580 - 10x) × x = (580x - 10x²)

Marginal Revenue = (dR/dx)

= (d/dx) (580x - 10x²)

= (580 - 20x)

B) Find the fixed cost and marginal cost function [Hint: fixed cost does not change with quantity produced]

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

The total cost function is a sum of the fixed cost and the variable cost.

The fixed cost is the unchanging part of the total cost function with changing levels of production (quantity produced), which is the term independent of x.

C(x) = 900 + 300x + 25x²

The only term independent of x is 900.

Hence, the fixed cost = 900

Marginal Cost function = (dC/dx)

= (d/dx) (900 + 300x + 25x²)

= (300 + 50x)

C) Find the profit function [Hint: profit is revenue minus total cost]

Profit = Revenue - Total Cost

Revenue = (580x - 10x²)

Total Cost = (900 + 300x + 25x²)

Profit = P(x)

= (580x - 10x²) - (900 + 300x + 25x²)

= 580x - 10x² - 900 - 300x - 25x²

= 280x - 35x² - 900

= (-35x² + 280x - 900)

D) Find the quantity that maximizes profit

To obtain this, we use differentiation analysis to obtain the maximum point of the Profit function.

At maximum point, (dP/dx) = 0 and (d²P/dx²) < 0

P(x) = (-35x² + 280x - 900)

(dP/dx) = -70x + 280 = 0

70x = 280

x = (280/70) = 4

(d²P/dx²) = -70 < 0

Hence, the point obtained truly corresponds to a maximum point of the profit function, P(x).

This quantity demanded obtained, is the quantity demanded that maximises the Profit function.

Hope this Helps!!!

8 0
2 years ago
Need some help with this
kramer

Answer:

Step-by-step explanation:

The total number of outcomes the two fair number cubes are thrown is 36. This can be seen by counting the outcomes shown on the table.

a) for a sum of 4, there are only 3 possible outcomes. They are 3,2 2,2 and 1,3

Therefore, the probability of getting a sum of 4 will be

3/36 = 1/12

b) for a sum of 5, there are only 4 possible outcomes. They are 4,1 3,2 2,3 and 1,4

Therefore, the probability of getting a sum of 4 will be

4/36 = 1/9

c)for a sum of 6, there are only 5 possible outcomes. They are 5,1 4,2 3,3 2,4 and 1,5

Therefore, the probability of getting a sum of 6 will be

5/36 = 5/36

The probability that the sum of the results of the throw is 4,5 or 6 would be

1/12 + 1/9 + 5/36 = (3 + 4 + 5)/36 = 12/36 = 1/3

7 0
3 years ago
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