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kvv77 [185]
2 years ago
13

Find two algebraic expressions for the area of each figure. First, regard the figure as one large rectangle, and then regard the

figure as a sum of four smaller rectangles.

Mathematics
1 answer:
lapo4ka [179]2 years ago
7 0
Area = length * width for a rectangle or square
Total area = (t+5)(t+3)
the rest of the areas can be seen here
http://prntscr.com/dc7jdg


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20 POINTS
sergey [27]

Solve. Note the equal sign. What you do to one side, you do to the other. Remember to follow PEMDAS.

First, distribute 5 to all terms within the parenthesis

5(w - 1) = (5)(w) + (5)(-1) = 5w - 5

Next, simplify. Combine like terms

5w - 5 - 2 = 5w + 7

5w - 7 = 5w + 7

Next, isolate the variable. Add 7 to both sides, and subtract 5w from both sides

5w (-5w) - 7 (+7) = 5w (-5w) + 7 (+7)

5w - 5w = 7 + 7

0 = 14 (Untrue).

0 solutions, or (A) is your answer

~<em>Rise Above the Ordinary</em>

5 0
2 years ago
Read 2 more answers
Decompose and use the distributive property to find the product of 5 × 7.3.
swat32

Answer:

36.5

Step-by-step explanation:

5(1+6.3)

6 0
3 years ago
A 50-gallon rain barrel is filled to capacity. It drains at a rate of 10 gallons per minute. Write an equation to show how much
makvit [3.9K]

Answer:

The quantity of water drain after x min is 50 (0.9)^{x}  

Step-by-step explanation:

Given as :

Total capacity of rain barrel = 50 gallon

The rate of drain = 10 gallon per minutes

Let The quantity of water drain after x min = y

Now, according to question

The quantity of water drain after x min = Initial quantity of water ×  (1-\dfrac{\textrm rate}{100})^{\textrm time}

I.e The quantity of water drain after x min = 50 gallon ×  (1-\dfrac{\textrm 10}{100})^{\textrm x}

or,  The quantity of water drain after x min = 50 gallon × (0.9)^{x}

Hence the quantity of water drain after x min is 50 (0.9)^{x}  Answer

4 0
3 years ago
Read 2 more answers
What is 3.8 repeating as a fraction in simplest form
Olin [163]
\bf 3.8888888\overline{8}\\\\&#10;-------------------------------\\\\&#10;x=3.8888888\overline{8}\qquad thus\qquad &#10;\begin{array}{llcll}&#10;10x&=&38.888888\overline{8}\\&#10;&&\downarrow \\&#10;&&35+3.8888888\overline{8}\\&#10;&&\downarrow \\&#10;&&35+x&#10;\end{array}&#10;\\\\\\&#10;10x=35+x\implies 9x=35\implies x=\cfrac{35}{9}

the idea being, you multiply the "x" by some power of 10 that moves the repeating part to the left of the decimal point and the split it like above.
6 0
3 years ago
Solution of this equation
lara31 [8.8K]
2.5y + 3x = 27
5x - 2.5y = 5

Align the variables to make solving this easier.

2.5y + 3x = 27
-2.5y + 5x = 5

You can see that the 2.5y and -2.5y cancel each other out. Then add the 3x and 5x, and 27 + 5.

3x = 27
5x = 5

8x = 32

Divide both sides by 8.

x = 4

Now input that x into one of the equations to get y. 

2.5y + 3(4) = 27
2.5y + 12 = 27
2.5y = 15
y = 6

The answer to this system of equations is x = 4, y = 6. (4, 6)
5 0
3 years ago
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