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wolverine [178]
3 years ago
5

A diamond ring that normally sells for $1,275 is on sale for $1,020. A ruby ring that normally sells for $290 is on sale for $20

3.
Mathematics
1 answer:
Elena-2011 [213]3 years ago
5 0

Answer:

what is the question?

Step-by-step explanation:

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Solve the following 3 × 3 system. Enter the coordinates of the solution below.
love history [14]
The system is:

i)    <span>2x – 3y – 2z = 4
ii)    </span><span>x + 3y + 2z = –7
</span>iii)   <span>–4x – 4y – 2z = 10 

the last equation can be simplified, by dividing by -2, 

thus we have:

</span>i)    2x – 3y – 2z = 4
ii)    x + 3y + 2z = –7
iii)   2x +2y +z = -5 


The procedure to solve the system is as follows:

first use any pairs of 2 equations (for example i and ii, i and iii) and equalize them by using one of the variables:

i)    2x – 3y – 2z = 4   
iii)   2x +2y +z = -5 

2x can be written as 3y+2z+4 from the first equation, and -2y-z-5 from the third equation.

Equalize:  

3y+2z+4=-2y-z-5, group common terms:
5y+3z=-9   

similarly, using i and ii, eliminate x:

i)    2x – 3y – 2z = 4
ii)    x + 3y + 2z = –7

multiply the second equation by 2:


i)    2x – 3y – 2z = 4
ii)    2x + 6y + 4z = –14

thus 2x=3y+2z+4 from i and 2x=-6y-4z-14 from ii:

3y+2z+4=-6y-4z-14
9y+6z=-18

So we get 2 equations with variables y and z:

a)   5y+3z=-9 
b)   9y+6z=-18

now the aim of the method is clear: We eliminate one of the variables, creating a system of 2 linear equations with 2 variables, which we can solve by any of the standard methods.

Let's use elimination method, multiply the equation a by -2:

a)   -10y-6z=18 
b)   9y+6z=-18
------------------------    add the equations:

-10y+9y-6z+6z=18-18
-y=0
y=0,

thus :
9y+6z=-18 
0+6z=-18
z=-3

Finally to find x, use any of the equations i, ii or iii:

<span>2x – 3y – 2z = 4 
</span>
<span>2x – 3*0 – 2(-3) = 4

2x+6=4

2x=-2

x=-1

Solution: (x, y, z) = (-1, 0, -3 ) 


Remark: it is always a good attitude to check the answer, because often calculations mistakes can be made:

check by substituting x=-1, y=0, z=-3 in each of the 3 equations and see that for these numbers the equalities hold.</span>
3 0
3 years ago
Read 2 more answers
For the equation given below, evaluate y′ at the point (−2,−1).<br><br> 3xy−3x−12=0.
SSSSS [86.1K]

Answer:

Y'=3xy-3x-12

Y'=F(-2,-1)=0

Step-by-step explanation:

The function of the equation at the point (-2,-1)

is where the equation make the function go to zero:

Y'=3xy-3x-12

Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12

F(-2,-1)=[6]-[-6]-12

F(-2,-1)=6+6-12

F(-2,-1)=12-12

F(-2,-1)=0

Solving for y

3xy-3x-12=0

y=4/x+x

Making y=0

\frac{4}{x}+x=0

x^{2} =-4

x=-2

So the values make the function go to zero

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2 years ago
What is the point called where the perpendicular bisectors of the sides of a triangle intersect
Vikki [24]
Answer: Circumcenter

This is the center of the circle that goes through the three vertices of the triangle. This circle is known as the circumcircle. It is the smallest circle possible in which the circle encompasses the triangle and none of the triangle spills outside the circle. 
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It could be 30 to 31 but February has 28 expected from a leap year with 29 days 
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Okay so what is the question
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