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musickatia [10]
2 years ago
12

Help me please I need it

Mathematics
1 answer:
Allushta [10]2 years ago
6 0

Answer:

(6,4)

Step-by-step explanation:

18/12 (simplify)

3/2

3/2 x 2/2 = 6/4 = (6,4)

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Find the 96th term of the arithmetic sequence 1, -12, -25, ...
goldenfox [79]

Answer:

The 96th term of the arithmetic sequence is -1234.

Step-by-step explanation:

first term (a)=1

second term (t2)=-12

common difference (d)= t2-a

d=-12-1

d=-13

96th term (t96)=?

We know that,

t96=a+(n-1)d

t96=1+(96-1)(-13)

t96=1+95(-13)

t96=1-1235

t96=-1234

6 0
3 years ago
I need help to these answers asap! 20 points!
iragen [17]

Answer:

Step-by-step explanation:

a is o.53 repeated

5 0
2 years ago
Read 2 more answers
Cookies are on sale! Today each cookie costs \$0.75$0.75dollar sign, 0, point, 75 less than the normal price. Right now if you b
seropon [69]

The <u><em>correct answer</em></u> is:

The equation is 7(c-0.75) = 2.80, and the regular price of a cookie is c = $1.15.

Explanation:

c is the regular price of a cookie. We know that today they are $0.75 less than the normal price; this is given by the expression c-0.75.

We also know if we buy 7 of them, the total is $2.80. This means we multiply our expression, c-0.75, by 7 and set it equal to $2.80:

7(c-0.75) = 2.80

To solve, first use the distributive property:

7*c-7*0.75 = 2.80

7c-5.25 = 2.80

Add 5.25 to each side:

7c-5.25+5.25 = 2.80+5.25

7c = 8.05

Divide each side by 7:

7c/7 = 8.05/7

c = $1.15.

7 0
3 years ago
Read 2 more answers
Find the volume of the solid whose base is the region Ix I Iy I &lt; 1 and whose vertical cross sections perpendicular to the y-
gavmur [86]

Answer:

volume of the solid = \frac{\pi }{3}

Step-by-step explanation:

As given , the region : |x| + |y| \leq 1

when y \geq 0 ,

|x| + y = 1

⇒|x| = 1 - y

when y ≤ 0 ,

|x| - y = 1

⇒|x| = 1 + y

The given region is the rectangle with sides (0, 5) , (0, -5), (5, 0), (-5, 0)

As given , the vertical cross section are semicircle

As we know that the area of semi circle  = \frac{1}{2}\pi  x^{2}

Now,

Volume = \int\limits^0_-1    {\frac{\pi }{2} (1+y)^{2}  } \, dy + \int\limits^1_0    {\frac{\pi }{2} (1-y)^{2}  } \, dy

            = \frac{\pi }{2} (\frac{(1+y)^{3} }{3} ) - \frac{\pi }{2} (\frac{(1-y)^{3} }{3} )

           = \frac{\pi }{6}[1-0] - \frac{\pi }{6}[0-1]

           = \frac{\pi }{6} + \frac{\pi }{6} = 2\frac{\pi }{6} = \frac{\pi }{3}

⇒volume of the solid = \frac{\pi }{3}

4 0
3 years ago
What does the expression 0.30y represent ?
Vilka [71]
The expression represents 0.30 times y, but I do not know the value of y.
5 0
3 years ago
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